Calculate Factor of Safety for Steel Hanger w/ 550 MPa Strength

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To calculate the factor of safety for a steel hanger with an ultimate strength of 550 MPa supporting a load of 64,000 N and a cross-sectional area of 7.4 cm², the stress due to the load must first be determined using the formula stress = load/area. After converting the area to square meters, the calculated stress is approximately 864.86 kPa. The factor of safety is then found by dividing the ultimate strength (550,000 kPa) by the allowable stress (864.86 kPa), resulting in a factor of safety of about 635.94. The final answer confirms that the calculations are correct, with the factor of safety being 6.359.
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Homework Statement



What is the factor of safety of a steel hanger having an ultimate strength of 550.00 MPa and supporting a load of 64000.000N. The steel hanger in question has a cross sectional area of 7.400cm squared

Homework Equations





The Attempt at a Solution


i understand the equation is ulitamate stress divided by allowable stress but the cross sectional area gives me problems. please show me a the steps i should take to find the factor of safety




well i went load/ area > 64000N/7.4cm squared = 8648.65 Pa


550 MPa = 550000kPa/8.648kPa (ultimate stress/allowable stress) =63594.11
63.59 as my answer is that correct ? if not please show me where i went wrong
 
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Given the load and the area, how do you find the working stress i.e. stress due to the load?
 
Load divided by area ...right ? , when it gives me cross sectional area do I need to do anything mathematically with it or do I plug that number in ?
 
walleye3 said:
Load divided by area ...right ? , when it gives me cross sectional area do I need to do anything mathematically with it or do I plug that number in ?

Well you have the formula

stress = load/area

And you are given both. You want to get the value of stress.
 
well i went load/ area > 64000N/7.4cm squared = 8648.65 Pa


550 MPa = 550000kPa/8.648kPa (ultimate stress/allowable stress) =63594.11
63.59 as my answer is that correct ? if not please show me where i went wrong
 
Check the units. cm2 ?
 
oh , i need metres squared
 
Load/Area= 64000N/0.074m= 864864.8649 Pa > 864.864 kPa
F/S = Ultimate stress/ Allowable Stress = 550 MPa/ 864.864 kPa > 550000 kPa/ 864.864kPa = 635.938


is (635.938 ) my answer ? (factor of safety) ??
 
walleye3 said:
Load/Area= 64000N/0.074m= 864864.8649 Pa > 864.864 kPa
F/S = Ultimate stress/ Allowable Stress = 550 MPa/ 864.864 kPa > 550000 kPa/ 864.864kPa = 635.938


is (635.938 ) my answer ? (factor of safety) ??



1 cm2 = 0.0001 m2
 
  • #10
1.0 cm2= ?? m2
 
  • #11
1 cm = 0.01 m ...
 
  • #12
okay thank you... i see my mistake
 
  • #13
64000 N/ 0.00074m2 = 86486486.49 Pa > 86486.48649 kPa
F/S Ultimate stress/Allowable Stress = 550 MPa/86486.48649 > 550000kPa /86486.48649= 6.359
 
  • #14
Allowable / Actual
 
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