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walleye3
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Homework Statement
What is the factor of safety of a steel hanger having an ultimate strength of 550.00 MPa and supporting a load of 64000.000N. The steel hanger in question has a cross sectional area of 7.400cm squared
Homework Equations
The Attempt at a Solution
i understand the equation is ulitamate stress divided by allowable stress but the cross sectional area gives me problems. please show me a the steps i should take to find the factor of safety
well i went load/ area > 64000N/7.4cm squared = 8648.65 Pa
550 MPa = 550000kPa/8.648kPa (ultimate stress/allowable stress) =63594.11
63.59 as my answer is that correct ? if not please show me where i went wrong
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