Recent content by WhiteHawk

The boulder is about the volume of a fluffy lazy boy chair (minus the back). My landscape friend estimated that weighed 1.5-2 tons. Imagine literally, a car running directly into this boulder, transferring enough energy to launch the rock 62 meters (I just measured my stride, 737 mm x 84...

What forum should I post this in, my friend died in a horrible car accident, some of us just want more answers I guess... Object A is in straight line motion Object B is static Object A impacts Object B Object A moves straight forward 60 m and rests Object B moves straight forward 76 m and...

There is a lot of crazy conspiracy chatter, if its true, then what type of equipment do I need to see the moon bases or Mars bases? Thank you. I'm a real human, curious son of a b.

The green circle is floating and can "move" with the system. A driveshaft with universal joints would be driving the green circle (like a car suspension can flex while the driveshaft is still able to turn).

I drew another diagram, with how I could maybe represent the scenario a little better. Blue circle is the pivot. Green circle is input torque. Tan box is force measuring device. The Important item, is the Magical Red lever to signify the torque, is this lever valid? See how I...

The square is real (mechanical object with no deflection). The one corner labled "bending moment" is on a pivot bearing, the square would rotate around that point. There is 300 ftlbs of torque being applied to the other point. The system would not actually move (with this design I would use a...

where did this moved?

I made a diagram with the calcs on it, should be fairly simple, I just need to make sure I'm doing it right or if I'm way off. link to the diagram These are the beginnings of my homemade engine dynamometer...I thank you for your assistance.

Thanks!

I'm experimenting some ideas and needed a verification of my formula. There is a torque arm of 15" with a force of 6000 lbs perpendicular to the axis of rotation. So that calculates to 7500 ft/lbs (6000*15/12). So on the same axis, there is a torque arm of 5" the must oppose this force...