Torque calculation, is this correct?

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The discussion centers on torque calculations involving a torque arm of 15 inches exerting a force of 6000 lbs, resulting in a torque of 7500 ft-lbs. To counter this torque with a shorter arm of 5 inches, the required opposing force was calculated to be 18000 lbs. This calculation is confirmed as valid, as a shorter moment arm necessitates a proportionally greater force to achieve equivalent torque. The conclusion emphasizes the relationship between moment arm length and required force in torque applications.

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WhiteHawk
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I'm experimenting some ideas and needed a verification of my formula.

There is a torque arm of 15" with a force of 6000 lbs perpendicular to the axis of rotation. So that calculates to 7500 ft/lbs (6000*15/12). So on the same axis, there is a torque arm of 5" the must oppose this force equally, I need that force required. I calculated 18000 lbs of opposing force with 7500 ft/lbs at the axis (7500/5*12).

Is this valid?

No its not a homework question :) I need to know how powerful a single disc brake on a truck is.

Thanks in advance.
 
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Yes. If you have 1/3 of the moment arm, you need 3 times the force to give the same torque.
 
Thanks!
 

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