Recent content by wiegetz

Homework Statement Simple question we have to answer: (Physics) How do I release the electrons from the cathode with a color filter? (The so called Photoelectric effect)Homework Equations none The Attempt at a Solution[/B] Here we have a conflict , the so called wave-particle duality, if...

I solved this problem. I needed to insert the given data simply into the formula, I thought that this attempt would be too simple. Can be marked as solved!

Sorry, I ment speed, not speech. The question is asked on a different language, so I tried to translate it. According to google, the correct meaning should be " Thermodynamic equilibrium "

Homework Statement With which speed goes the Mass through the Equilibrium? Homework Equations Es = 1/2*D*s2 Ekin = 1/2*m*v2 Epot = m*g*h Energy in the zero point = below/ under highest Point: Epot = 1kg * 9,81N/kg*0.67m ≈ 6.573Nm Equilibrium : Ekin, Epot, Es Lowest Point: Es= 0 Ekin = 0...

Solved, thanks for the help!

Might be correct, but that question is supposed to be really simple, as the teacher told. I repeat again: The only thing he told is that we need to google up the Suns mass, nothing more.

Answer same as followed: Solution: No, 11,2km/s is far not enough to wrest away from Suns gravitational field. We did not talk about bodies' pull at all. Do you think that it would be OK to use 42.1 km/s as a result then? [SIZE=16px][FONT=PT Sans]

Thanks for the answers! The teacher said that this is quite simple and that we only need to google up the mass of Sun. About the radial distance : I am sure that you are correct, but the teacher would mention it if we needed that as well. Is there no other possiblity to calculate it, starting...

Homework Statement Are 11,2km/s enough, to wrest away from the Suns gravitational field? (We are departing away from the Earth planet, away from the sun) Here I am unsure if I should use Suns Radius or Earths Radius r. I think that Suns Radius would be more logical, since the problem is about...

Homework Statement One of Jupiters Moons runs on a circle with the radius r1= 420000km in T1=1,77d. How big is Jupiters Mass? Can you calculate the Mass of the Moon with this as well? γ = 6,672*10-11m3*kg-1*s-2 (gravitational constant) Homework Equations I used following equation...

I will use my result to present, since the teacher did not say anything about the sun, and since we started the topic recently, I do not think that he expected us to know it. If I have more questions I will ask, thanks for the help!

Finally, I hope: I continued from where you stopped: T22/a23 = 1 (Inserting 2 years for T2) 22/a23 = 1 (equivalence transformation with *22 to the right) a23 = 1*22 ( pull 3rd root to the right) a2 = 3√1*22 a2 ≈ 1,5874 Sentence = Planet is ≈ 1,5874 AU away from Earth, which equals ≈...

In short: $$\frac{T_2^2}{a_2^3} = \frac{T_1^2}{a_1^3}$$ I see know how easy it is. Could you say if my result is correct? : I inserted for T22 2 years, and for a 1 AU (Since how you said, but 150000000km equals 1,0026880684005897 AU (1AU) ) . Then I became 4 (I think 4 AU?) As a result, which...

If you need to, why not? I doubt it will help you though solving my problem. I tried out following things: T2/a3 and a3/T2 and a/T and T/a some are sensless, but trying does not harm. Still I got a bad result: What I need is, if I increase T, the result does need to increse, not decrease...

Thank you for your response. Sadly I still do not know what to do, if I use the formula you gave to me, I get approx. 1,18-24 which can be only wrong. I do not know what to do with this "simple" formula. Frustrating :( I need to get a formula with this one, where the results increses if I...