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With which speech goes the Mass through the Equilibrium?

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  1. May 22, 2016 #1
    1. The problem statement, all variables and given/known data
    With which speed goes the Mass through the Equilibrium?

    2. Relevant equations
    Es = 1/2*D*s2
    Ekin = 1/2*m*v2
    Epot = m*g*h

    Energy in the zero point = below/ under

    highest Point: Epot = 1kg * 9,81N/kg*0.67m
    ≈ 6.573Nm

    Equilibrium : Ekin, Epot, Es

    Lowest Point: Es= 0 Ekin = 0, Epot = 0
    3. The attempt at a solution
    I have no Idea what I have to do. I found out that the total Energy needs to be approx. 6,573Nm of the system.
     
    Last edited: May 22, 2016
  2. jcsd
  3. May 22, 2016 #2

    SteamKing

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    Your problem statement makes no sense.

    What speech? What equilibrium?
     
  4. May 22, 2016 #3
    Sorry, I ment speed, not speech. The question is asked on a different language, so I tried to translate it. According to google, the correct meaning should be "
    Thermodynamic equilibrium

    "
     
  5. May 22, 2016 #4

    SteamKing

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    OK, things are a little clearer now. But what about the particulars of this problem? What does 0.67 m have to do with anything?
     
  6. May 22, 2016 #5
    I solved this problem. I needed to insert the given data simply into the formula, I thought that this attempt would be too simple. Can be marked as solved!
     
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