Right.
So I've just broken it up into x and y components
Fx=Wsin25-.12(Wcos(25))=m*a
I calculated for acceleration in the x plane, and found a=3.08 m/s^2
Then I just did
Vf=sqr(2ax+V0^2)
sqr(2(3.08)(60)+4^2)= Vf= 19.6 m/s
Does this seem correct?
Homework Statement
A 50Kg skier skies down a 25 degree slope. at the top of the slope her speed is 4m/s and accelerates down the hill. the coefficient of friction is 0.12 between skies and snow. ignoring air resistance calculate her speed at point that is displaced 60m downhill...