Recent content by Will M

he was attacked by a flock of birds while cleaning his bathroom sink out If you named a burger chain Heisenburger, would you be able to tell what was in the food and how much it cost at the same time?

Yeah, I caught that when I checked it over, but thanks, because you've been a real help! :biggrin:

Ah, I think I see it now. Thanks! :biggrin: Would this be correct: mgsin\theta - \mu mgcos\theta=ma mg(sin\theta - \mu cos\theta)=ma g(sin\theta - \mu cos\theta)=a \mu g +g(sin\theta - cos\theta)=a \mu +sin\theta - cos\theta=a/g \mu=a/g -sin\theta + cos\theta \mu=2\Delta...

I could express it as F_N=mgcos\theta right? Then I could substitute it for F_N in F_f=\mu F_n After rearranging to solve for μ, it would be \mu=F_f/mgcos\theta Substituting the fifth line of my original solution for F_f would give me \mu = \left(2\Delta d/\Delta t^{2} - g sin...

There is no applied force, do you mean net force? Also, I'm looking for the coefficient of friction, not the force of friction, otherwise I would have stopped at the line Ff = 2Δd/Δt² - g sin θ

Ok, I realize that since μ is a constant, it shouldn't be mass dependent. I also know that since there is no acceleration in the perpendicular direction, the normal force is opposed by, and has a magnitude equal to, the perpendicular component of the force of gravity. I've expanded this to mg...

How would I express F[SIZE="1"]N in simpler terms?

[SOLVED] Coefficient of friction on an inclined plane Homework Statement The problem I have is to determine the coefficient of kinetic friction between two wooden objects, a block and a ramp, using the fewest measurements possible. The initial velocity will be 0. I can measure the angle of...