Recent content by Willian93
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Gravitational Field: Proton & Electron Mass Ratio
Homework Statement if a proton and a electron put in a gravitational field, what is their ratio compare to one another? Homework Equations fg= GMm/r^2 mass of a proton = 1.67 x 10^-27 kg mass of a electron= 9.11 x 10^-31 kg The Attempt at a Solution i tried to divided them out, i...- Willian93
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- Field Gravitational Gravitational field
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- Forum: Introductory Physics Homework Help
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Use the definition of derivative to find the derivative of tan(x)
Homework Statement use the definition of derivative to find the derivative of tan(x) Homework Equations Tan(x)= sinx/cosx The Attempt at a Solution i used sinx/cosx, and then use quotient rule, not sure if it is call "definition of derivative"so, is there anyway i can use...- Willian93
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- Definition Derivative
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- Forum: Calculus and Beyond Homework Help
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Projectile motion maximum range
Homework Statement a projectile is launched from level ground at some angle to the horinzontal. Which of the following must be zero for a projectile to achieve maximum range? vx, vy, delta dx, delta dy or a Homework Equations The Attempt at a Solution i thought to achieve maximum...- Willian93
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- Maximum Motion Projectile Projectile motion Range
- Replies: 2
- Forum: Introductory Physics Homework Help
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Calculating P'(1) for p(x)=f(x^3)
Homework Statement if p(x)= f(x^3), find P'(1) Homework Equations The Attempt at a Solution can i do the derivative of x^3 is 2x^2, then substitute to get f(2x^2)?, then substitute 1 for x?- Willian93
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- Replies: 4
- Forum: Calculus and Beyond Homework Help
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Limits at infinity of trigometric function
Homework Statement lim (x→pi)〖sin(x-pi)/(x-pi)〗 Homework Equations i don't know if we should use trig identity sin(a-b)= sinA cos B- CosA sin B The Attempt at a Solution i use identities to solve that, i did not get the answer. i tried to multiply by conjugate, did not work also.- Willian93
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- Function Infinity Limits
- Replies: 2
- Forum: Calculus and Beyond Homework Help
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What is the relationship between the domain and range of a function?
Domain is all the possible values that X could be Range is all the possible values that Y could be example: determine the domain and range of y= x^2 when u sketched the graph, you can see x could be anything, it keeps going forever there for D( -infinity, +infinity) for y, however...- Willian93
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- Forum: Precalculus Mathematics Homework Help
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How many unique ways are there to arrange 5 people around a circular table?
think about how 5 people sit in a row. in circular shape, we can't exactly know the start point. So we Freeze one person and all other 4 people rotates, so you are actually in a right directions- Willian93
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- Forum: Precalculus Mathematics Homework Help
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What is the asympote of this graph?
in the graph 2^x, doesn't matter what value for x, y NEVER can be zero or negative, because this is exponential relation. try x=-100000000, y is extremely small but can never be zero. The asymptote for that graph is y=0, where y can never approach value closer to zero.- Willian93
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- Forum: Precalculus Mathematics Homework Help
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Solving for y: Why/How do y and e^x switch places?
so what exactly is the equation? i don't get what you are trying to say. is this about Inverse Function or Logarithm?(log and ln?)- Willian93
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- Forum: Precalculus Mathematics Homework Help
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"Solving Coefficient of x^n in Binomial Expansion
are u sure you have to find a cofficient contain x^n? because u should have a specific value for n, so that you could find the cofficient infront of it, or you should at least have which term you are looking for.- Willian93
- Post #2
- Forum: Precalculus Mathematics Homework Help
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Measure of the smallest angle in the triangle
first you need to find side c using cosine law c2=a2 +b2=2abcosC then use sine law to find angle A, cause the higher angle, the longer the side, since side A is the shortest, which means angle A is the smallest.- Willian93
- Post #8
- Forum: Precalculus Mathematics Homework Help
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Finding Solutions for Sin 2θ = Sin θ in the Interval 0 ≤ θ ≤ 360?
sin2A = SinA 2SinAcosA = SinA 2SinAcosA - SinA = 0 SinA (2CosA-1)= 0 sinA = 0 2CosA-1=0 A= 0,180,360 A= 60, 300 i didn't check this, i just did this real quick, if i was wrong sorry, but i think i did it right Hope that helps- Willian93
- Post #2
- Forum: Precalculus Mathematics Homework Help