Recent content by woodenbox
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Length contraction problem in special relativity
Oh yes I see your point...thank you for the response :) So I thought about this a lot and realized one key thing: there are two γ's in the scenario, one for u and one for v. The γ in L = L0/γ uses u (as in 1/sqrt(1 - u^2/c^2)) while the Lorentz transformation equation's γ uses v (as in...- woodenbox
- Post #3
- Forum: Introductory Physics Homework Help
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Length contraction problem in special relativity
Homework Statement A rod of proper length L0 oriented parallel to the x-axis moves with speed u along the x-axis in S. What is the length measured by an observer in S'? Homework Equations Relativistic relative velocity: For an object moving with speed u in S, its speed u' in S' = (u - v)/(1...- woodenbox
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- Contraction Length Length contraction Relativity Special relativity
- Replies: 3
- Forum: Introductory Physics Homework Help
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Quality factor of driven damped oscillating pendulum
Homework Statement A small cuckoo clock has a pendulum 25 cm long with a mass of 10 g and a period of 1 s. The clock is powered by a 200 g weight which falls 2 m between the daily windings. The amplitude of the swing is 0.2 rad. What is the Q (quality factor) of the clock? How long would the...- woodenbox
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- Damped Oscillating Pendulum Quality
- Replies: 1
- Forum: Advanced Physics Homework Help
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Finding local min, max, and saddle points in multivariable calculus
that does make a lot of sense... i never thought to take a more direct approach. thank you for your help!- woodenbox
- Post #4
- Forum: Calculus and Beyond Homework Help
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Finding local min, max, and saddle points in multivariable calculus
got the answer, for anyone else who looks this up. Rewriting the function as f(x, y) = (x - y)^2 + 1, we see that the minimum value must be 1 (since 0 is the smallest value of a square), and this is attained whenever y = x (i.e., points of the form (x, x)).- woodenbox
- Post #2
- Forum: Calculus and Beyond Homework Help
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Finding local min, max, and saddle points in multivariable calculus
Homework Statement Find the local maximum and minimum values and saddle point(s) of the function. f(x,y) = 1 + 2xy - x^2 - y^2 Homework Equations The Second Derivative Test: let D = D(a,b) = fxx(a,b)*fyy(a,b) - [fxy(a,b)]^2 if D > 0 and fxx(a,b) > 0, then f(a,b) is a local minimum...- woodenbox
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- Calculus Local Max Multivariable Multivariable calculus Points
- Replies: 3
- Forum: Calculus and Beyond Homework Help