Oh yes I see your point...thank you for the response :)
So I thought about this a lot and realized one key thing: there are two γ's in the scenario, one for u and one for v. The γ in L = L0/γ uses u (as in 1/sqrt(1 - u^2/c^2)) while the Lorentz transformation equation's γ uses v (as in...
Homework Statement
A rod of proper length L0 oriented parallel to the x-axis moves with speed u along the x-axis in S. What is the length measured by an observer in S'?
Homework Equations
Relativistic relative velocity:
For an object moving with speed u in S, its speed u' in S' = (u - v)/(1...
Homework Statement
A small cuckoo clock has a pendulum 25 cm long with a mass of 10 g and a period of 1 s. The clock is powered by a 200 g weight which falls 2 m between the daily windings. The amplitude of the swing is 0.2 rad. What is the Q (quality factor) of the clock? How long would the...
Homework Statement
A small cuckoo clock has a pendulum 25 cm long with a mass of 10 g and a period of 1 s. The clock is powered by a 200 g weight which falls 2 m between the daily windings. The amplitude of the swing is 0.2 rad. What is the Q (quality factor) of the clock? How long would the...
got the answer, for anyone else who looks this up.
Rewriting the function as f(x, y) = (x - y)^2 + 1,
we see that the minimum value must be 1 (since 0 is the smallest value of a square),
and this is attained whenever y = x (i.e., points of the form (x, x)).
Homework Statement
Find the local maximum and minimum values and saddle point(s) of the function.
f(x,y) = 1 + 2xy - x^2 - y^2
Homework Equations
The Second Derivative Test: let D = D(a,b) = fxx(a,b)*fyy(a,b) - [fxy(a,b)]^2
if D > 0 and fxx(a,b) > 0, then f(a,b) is a local minimum...