Recent content by woox

I did and didn not use the HH eq, not do i understand what you mean by dilution. I also read link, and this is onlything really useful that I understood but still does not explain what I am doing wrong: It would be great if you told me what I am doing wrong...

k... using ICE table below:

Even if I did not use HH equation I am getting the wrong answer.

Homework Statement Calculate the pH at the equivalence point for the titration of 0.20 M NH3 with 0.20 M HCl? Kb of ammonia is 1.8e-5 This is just a old test I am going over, I managed to get a pH of 4.98. but that is not right the right answer is 5.12 and I can't figure out why. I would...

No one is going to give you the answer without any work. Do your own homework and ask for help here if you need it

f = 2(x-2)/(x+2) and g = 4(x-2)(x+2) the common denominator would be (x+2) so: 2(x-2)-4(x-2)(x+2)(x+2)/(x+2) now do I multiple variables together, and subtract likes leaving it over denominator? (That gave me this mess: [(4x^3)+(8x^2)-14x+36]/(x+2) )

Cool, and for the second one I think i figured it out: f = 2(x-2)/(x+2) and g = 4(x^2 - 4) = 4(x-2)(x+2) We can factor out the x-2 and x+2, which gives us: (x+2)(x-2)(-2) I am not sure if I should multiple this out or leave it as is?

x^2/[(-16x^2)+4] ?

ah so the common denominator being x^2 resulting in: [(-16x^2)+4]/x^2 correct? (multiplied by x^2/x^2)

it should be: g(1/x) = 4(1/x)^2 - 16 g(1/x) = 4(1^2/x^2) - 16 g(1/x) = 4(1/x^2) - 16 g(1/x) = (4/x^2) - 16 g(1/x) = 4[(1/x^2) - 4] correct?

So : 4(1/1/x)^2 - 16 taking inverse: 4(1/x)^2 - 16 ?

ok so I start with: gx=4x^2-16 inverse of that is: 1/[4x^2]-16 Then I plugin (1/x) and get: 1/[4(1/x)^2]-16 Is that correct so far? Then do I flip it back? making it: ([4(1/x)^2]-16)^-1

Did that and got : [(x^2)-1] / 16 Is that correct?

For 1/[g(1/x)] I did was plug in (1/x) in 1/g(x) which gave me -> 1/[4*((1/x)^2)] and then I just flipped it adding the ^-1 For the fx-gx, I did see that but I didnt know what to do from there either, i still needed a common denominator and basically it sort of lead back to what I got.

Homework Statement f(x)=(2x-4)/(x+2) g(x) = 4x2-16 find and simplyify: 1/[g(1/x)] f(x)-g(x) Homework Equations The Attempt at a Solution For 1/[g(1/x)]: I got (-16x^2+4)/(x^2), but I can't figure out how to simplify this down further, this assignment had other problems...