Titration: Calculate pH at Equivalence Point (NH3 & HCl)

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Discussion Overview

The discussion revolves around calculating the pH at the equivalence point for the titration of 0.20 M NH3 with 0.20 M HCl, focusing on the methodology and reasoning behind the calculations involved in this acid-base titration.

Discussion Character

  • Homework-related, Technical explanation, Debate/contested

Main Points Raised

  • One participant presents a calculation of pH at the equivalence point as 4.98 but believes the correct answer should be 5.12, expressing confusion over the discrepancy.
  • Another participant advises against using the Henderson-Hasselbalch equation and emphasizes the importance of considering dilution effects in the calculation.
  • A participant requests to see the details of the calculations to identify potential errors, indicating that without this information, it is difficult to provide assistance.
  • There is a reiteration of the need for clarity on the dilution aspect, with one participant expressing frustration over not understanding how it applies to their situation.
  • Another participant suggests looking into dilution effects, noting that mixing two solutions changes their concentrations due to the final volume differing from the initial volumes of the reagents.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correct method for calculating the pH at the equivalence point, with multiple viewpoints on the use of the Henderson-Hasselbalch equation and the significance of dilution effects remaining contested.

Contextual Notes

Participants express uncertainty regarding the application of dilution in their calculations and the implications of using the Henderson-Hasselbalch equation, which has not been resolved in the discussion.

woox
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Homework Statement


Calculate the pH at the equivalence point for the titration of 0.20 M NH3 with 0.20 M HCl? Kb of ammonia is 1.8e-5

This is just a old test I am going over, I managed to get a pH of 4.98. but that is not right the right answer is 5.12 and I can't figure out why. I would assume you could use the henderson equation but I only get 4.98 which is wrong.

Any help?
 
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So show details of your work, hard to say what you did wrong not knowing what you did.
 
Borek said:
So show details of your work, hard to say what you did wrong not knowing what you did.
k... using ICE table below:

2145854.jpg
 
Please reread my very first post in this thread. Every word of it.
 
Borek said:
Please reread my very first post in this thread. Every word of it.

I did and didn not use the HH eq, not do i understand what you mean by dilution.

I also read link, and this is onlything really useful that I understood but still does not explain what I am doing wrong:
In the case of titration of weak base with strong acid, situation is very similar - pH at the equivalence point is determined by the weak base salt hydrolysis. Thus we need pKa of conjugated acid to calculate H+ and pH. Check lecture and cheat sheet mentioned above for details.

It would be great if you told me what I am doing wrong...
 
Try here: dilution effects. Generally speaking, you have mixed two solutions, concentrations have changed as the final volume differs from the initial for each reagent.
 

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