Titration: Calculate pH at Equivalence Point (NH3 & HCl)

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To calculate the pH at the equivalence point for the titration of 0.20 M NH3 with 0.20 M HCl, it is essential to consider the dilution that occurs when the two solutions are mixed. The correct pH at the equivalence point is 5.12, not the 4.98 initially calculated. The Henderson-Hasselbalch equation should not be used in this scenario, as it is not applicable at the equivalence point. Instead, an ICE table can help clarify the changes in concentration due to dilution. Understanding the dilution effects is crucial for obtaining the correct pH value in acid-base titrations.
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Homework Statement


Calculate the pH at the equivalence point for the titration of 0.20 M NH3 with 0.20 M HCl? Kb of ammonia is 1.8e-5

This is just a old test I am going over, I managed to get a pH of 4.98. but that is not right the right answer is 5.12 and I can't figure out why. I would assume you could use the henderson equation but I only get 4.98 which is wrong.

Any help?
 
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Borek said:
acid base titration equivalence point calculation

Note: you should not use Henderson-Hasselbalch, however, you should not forget about dilution.

Even if I did not use HH equation I am getting the wrong answer.
 
So show details of your work, hard to say what you did wrong not knowing what you did.
 
Borek said:
So show details of your work, hard to say what you did wrong not knowing what you did.
k... using ICE table below:

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Please reread my very first post in this thread. Every word of it.
 
Borek said:
Please reread my very first post in this thread. Every word of it.

I did and didn not use the HH eq, not do i understand what you mean by dilution.

I also read link, and this is onlything really useful that I understood but still does not explain what I am doing wrong:
In the case of titration of weak base with strong acid, situation is very similar - pH at the equivalence point is determined by the weak base salt hydrolysis. Thus we need pKa of conjugated acid to calculate H+ and pH. Check lecture and cheat sheet mentioned above for details.

It would be great if you told me what I am doing wrong...
 
Try here: dilution effects. Generally speaking, you have mixed two solutions, concentrations have changed as the final volume differs from the initial for each reagent.
 
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