Recent content by wormhole

Hi the problem i have sounds something like that: there is a piece of glass with metal cover(on one side) in vacuum. light incident on metal surface. if you look at the glass from the metal surface side it appears red but when you look at it from other side it appears blue. given wave...

ok, i took the formula \tan(a+b)=\frac{\tan(a)+\tan(b)}{1-\tan(a)\tan(b)} using this formula i can simplify the equation to become: \frac{2\frac{df}{dx}}{1-{(\frac{df}{dx})}^2}=\frac{f(x)}{x-x_0} is it possible to solve it?

i'm trying to find a mirror shape which focuses a light at some specific point x_0 the initial equation i derived for determining the shape of the mirror is: (assuming that light rays fall parallel to x-axis - light source is very far from the mirror) f(x) is the shape I'm trying to...

ok i figured it out any polinom of degree two will do it thanks

how can i solve this differential equation? {(\frac{d^2y}{dx^2})}^2+ay(x)+b=0

thanks a lot:)

ok... so at when particle moves from (a) to (b) its velocity vector point to left while when particle moves from (c) to (d) its velocity vector points to right. so according to right-hand rule \vec{L} changes direction... right?

L=rmv\sin(\alpha) so if one wants to maintain L constant then if r increases then v\sin(\alpha) decreases and if r closer to force center the v\sin(\alpha) is larger. i don't see any contradiction to this on the picture(or maybe the direction of L is what matters?) when particle is moving...

i asked my classmates about the solution and some say that there is no need to use expansion series... i'm not sure what they did is right..so when i get the official solution(next week) i will give you a link to it

i already know that i was wrong... this trajectory is not possible under central force but i don't see how can i say that by the picture.

i know that one of the angular momentum vector components is conserved so the entire motion is in the plane(perpendicular to that component) also usual energy is conserved...

\frac{A_0}{r}=2.1 =>r=\frac{A_0}{2.1} finaly y_0^2+x^2=r^2=(\frac{A_0}{2.1})^2

i hope i right take origin as place where jackhammer is y_0 is where supervisor at the beginning. you know that amplidute falls with the distance as \frac{A_0}{r} assume that supervisor walks in positive x direction distance s

Hi we just studied motion under central force. we got the following question... is this possible trajectory(see attachment) under central force and force source is outside the loop? (my answer is that it is possible if force source is repulsive) whatever the answer is how can i explain it...

i'll try to do that... from the plots i did the r where u(r) is at minimum is very close to zero i have to take only first term in e^{-ar} expansion series otherwise i get an third order equation