Recent content by xcompulsion

im sorry. i don't understand..

Homework Statement Runner A runs at 6.0m/s for 10s. Runner B accelerates from 4.0 m/s to 10.0 m/s steadily in 10s. How far does Runner A go in 10s? How far does Runner B go in 10s? At what time did Runner B pass Runner A if they were both at the same position at t=0? Homework Equations d=...

v2^2 = v1^2 + 2(a)(d) 0 = (16.67)^2 + 2(-4.155)(d) 0 = 277.9 + (-8.31)(d) -277.9 / -8.31 = (-8.31)(d) / (-8.31) d = 33.44m so, 33.44/1000 = 0.033km! thank you so much :smile:

Okay, so after converting all the units to m/s.. first part: v1 = 40km/h = 11.11m/s v2 = 10km/h = 2.8m/s t=2.0s a = v/t = (2.8m/s - 11.11m/s) / 2.0s = -4.155m/s^2 second part: v1 = 60km/h = 16.67m/s v2 = 0km/h = 0m/s a = -4.155m/s^2 d = ? v2^2 = v1^2 + 2(a)(d) 0 = (16.67)^2 +...

I'm thinking about calculating the acceleration using the givens from the first part, to calculate the second part. so using the equation, v2^2 = v1^2 + 2(a)(t) But what has gotten me really puzzled is the seconds, the hours, and the kilometers.

A car traveling at 40km/h has it's speed reduced to 10km/h in 2.0s. Assuming that the same deceleration would be in effect, find how far the car will travel in coming to rest from a speed of 60km/h?