How far will a car travel when decelerating from 60km/h to 10km/h in 2.0s?

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Homework Help Overview

The problem involves calculating the distance a car will travel while decelerating from 60 km/h to 10 km/h over a period of 2.0 seconds. The discussion centers around the concepts of kinematics and the appropriate equations for motion under uniform acceleration.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss starting the problem by calculating acceleration based on given values from a related scenario. There is a focus on unit conversion and the correct application of kinematic equations.

Discussion Status

Some participants have offered guidance on unit conversion and the correct form of the kinematic equation. There is an ongoing exploration of the calculations involved, with some participants questioning the accuracy of earlier steps and results.

Contextual Notes

Participants are navigating issues related to unit conversions between kilometers per hour and meters per second, as well as ensuring all variables are correctly applied in the equations. There is a noted confusion regarding the use of time versus distance in the equations discussed.

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A car traveling at 40km/h has it's speed reduced to 10km/h in 2.0s. Assuming that the same deceleration would be in effect, find how far the car will travel in coming to rest from a speed of 60km/h?
 
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What are you thoughts on how to start this problem?
 
hage567 said:
What are you thoughts on how to start this problem?
I'm thinking about calculating the acceleration using the givens from the first part, to calculate the second part.

so using the equation,
v2^2 = v1^2 + 2(a)(t)

But what has gotten me really puzzled is the seconds, the hours, and the kilometers.
 
That's the right approach, but that equation is not quite right. That t should be a d (as in distance). Check for another equation.

You will need to convert your quantities so they are all in the same units. I usually work in meters and seconds in these questions. I would start with that before you do anything else.
 
hage567 said:
That's the right approach, but that equation is not quite right. That t should be a d (as in distance). Check for another equation.

You will need to convert your quantities so they are all in the same units. I usually work in meters and seconds in these questions. I would start with that before you do anything else.
Okay, so after converting all the units to m/s..

first part:
v1 = 40km/h = 11.11m/s
v2 = 10km/h = 2.8m/s
t=2.0s
a = v/t = (2.8m/s - 11.11m/s) / 2.0s = -4.155m/s^2

second part:
v1 = 60km/h = 16.67m/s
v2 = 0km/h = 0m/s
a = -4.155m/s^2
d = ?

v2^2 = v1^2 + 2(a)(d)
0 = (16.67)^2 + 2(-4.155)(d)
0 = 277.9 + (-831)(d)
d = 831 - 277.9
d = 553.1m/s

However, the correct answer to this question is 0.033km..
 
That -831 is wrong, you missed the decimal place!

Also, you didn't solve for d correctly. There should be division involved. Try again.
 
v2^2 = v1^2 + 2(a)(d)
0 = (16.67)^2 + 2(-4.155)(d)
0 = 277.9 + (-8.31)(d)
-277.9 / -8.31 = (-8.31)(d) / (-8.31)
d = 33.44m

so, 33.44/1000 = 0.033km!

thank you so much :smile:
 
You're welcome!
 

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