When Does Runner B Pass Runner A?

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Runner A travels 60 meters in 10 seconds at a constant speed of 6.0 m/s. Runner B accelerates from 4.0 m/s to 10.0 m/s, covering 70 meters in the same time frame. To determine when Runner B passes Runner A, the equation vt = ½(v1+v2)t is suggested, requiring a relationship for v2 in terms of time. The discussion highlights the need to find the specific time at which Runner B overtakes Runner A. Clarification is requested by a participant who is struggling to understand the approach.
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Homework Statement


Runner A runs at 6.0m/s for 10s. Runner B accelerates from 4.0 m/s to 10.0 m/s steadily in 10s. How far does Runner A go in 10s? How far does Runner B go in 10s? At what time did Runner B pass Runner A if they were both at the same position at t=0?

Homework Equations


d= v*t, d = 1/2(v1+v2)*t

The Attempt at a Solution



Runner A:
d = v*t
d = (6.0m/s)(10s)
d = 60m

Runner B:
d = 1/2(v1+v2)*t
d = 1/2(4m/s+10m/s)*(10s)
d = 1/2(14m/s)*(10s)
d= 70m

so therefore at 10s, Runner B has already surpassed Runner A by 10m. But how would you find when Runner B passed Runner A?


Many thanks.
 
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Do you see that you want to find t such that vt = ½(v1+v2)t? How can you write v2 in terms of t?
 
Tedjn said:
Do you see that you want to find t such that vt = ½(v1+v2)t? How can you write v2 in terms of t?

im sorry. i don't understand..
 
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