Recent content by Yossi33

yes, that is why i stated that my first try was to compare the displacements of point M , and the solution is 2 equations of deformations because the structure is twice statically indeterminate but i try to solve that and i dont know if its right or no . can you tell me if its ok or if im in the...

no , also in the diagram you can see that it is a half node and the upper structure TMS is continous . and i did some extra black there to emphasize the rigidity of the 90 degree. .- edit - that is why i said that the structure is two times statically indeterminate.

W the uniform load acts on the beam , that casues the member NM to stretch and as a result , bending down the upper structure.

Hi, i'm struggling with that problem , i need to find the distance that point N went down.My way of thinking is that the structure is twice not statically determined because of the beam MN and beacuse of the left support which is also unnecessary in order for equilibrium. My 2 equations of...

But if f1 is compression instead of tension it will be clockwise and counter the p forces moment? why to assume it’s only directions is tension ?

hello, i struggle with this kind of questions and i don't understand the way of thinking and how to solve this. in the first picture i don't understand why Moments about point Aare a*F1 because there is the 2 P forces that do moments.? in the second problem i can't understand why there are 3...

for example in this problem a 3knm moment is applied at point G of CDE member and now if i dismember CBA and try to calculate moment in Z axis do i need to take this moment?

hello, i have a question in this topic of frames in mechanic engineering, if i have a problem with 3 or 4 members that connected and a moment of couple is applied at specific frame,a moment of couple is general and is applied at any given point of the body. so when i dismember the frame and draw...

thank you all for the help

https://ibb.co/kgYgSL9 is it correct?

do you mean the screw at the center of the rod?

the force by the spring exert a moment on the rod equal to F*(half length of rod) ( the perpendicular distance for the line of action of the force and the rotation axis) if i denote the rod L and F is kx then the moment about the rotation axis , exerted by the spring is kx*0.5*L

but how can i express the partial mass of the rod that is attached to the rod?

https://ibb.co/LPhzYhf you mean like this? it's an overhead view so the weight and normal cancel each other so there is only the kx of the spring.

hello, i have some diffuculties with this problem, there's the point where the spring is attached to the rod and according to the equation of time period of physical pendulum , h represent the distance from the COM and the pivot point. here the pivot point is at the COM. and i know that it can't...