How Does Pivot Point Location Affect the Time Period of a Physical Pendulum?

AI Thread Summary
The discussion centers on the relationship between pivot point location and the time period of a physical pendulum, specifically addressing a problem involving a spring attached to a rod. The original poster expresses confusion about calculating the time period when the pivot is at the center of mass (COM), noting that this would theoretically lead to an infinite time period. Participants suggest that the problem resembles a spring-mass oscillation rather than a traditional pendulum scenario and encourage the use of free body diagrams (FBD) to analyze the forces involved. The conversation progresses to the moments exerted by the spring and the moment of inertia of the rod, leading to the formulation of an equation of motion. The thread concludes with the original poster confirming their understanding and thanking the contributors for their assistance.
Yossi33
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Homework Statement
Physical pendulum time period
Relevant Equations
T=2pi*(I/mgh)
hello, i have some diffuculties with this problem, there's the point where the spring is attached to the rod and according to the equation of time period of physical pendulum , h represent the distance from the COM and the pivot point. here the pivot point is at the COM. and i know that it can't be (then the T would be infinity). i don't know if i need to calculate the T of the spring and it would be the same but than what part of the mass is attached to it.
thanks for the help.
https://ibb.co/nsGTrQw

[Mentor Note -- Newbie OP reminded to upload images to PF to avoid confusion when externally linked images disappear (and the associated suspicions of student cheating). All associated images have been uploaded by the Mentors]
1647018355455.png
 
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It looks more like a spring-mass oscillation problem than a pendulum problem to me. Can you show us your FBD for the horizontal lever during small oscillations?
 
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I think you need some specific analysis and an equation of motion for this problem.
 
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berkeman said:
It looks more like a spring-mass oscillation problem than a pendulum problem to me. Can you show us your FBD for the horizontal lever during small oscillations?
https://ibb.co/LPhzYhf
you mean like this? it's an overhead view so the weight and normal cancel each other so there is only the kx of the spring.

1647018429135.png
 
Yossi33 said:
https://ibb.co/LPhzYhf
you mean like this? it's an overhead view so the weight and normal cancel each other so there is only the kx of the spring.
That's a good start.
 
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PeroK said:
That's a good start.
but how can i express the partial mass of the rod that is attached to the rod?
 
What have you learned about moments?
 
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pbuk said:
What have you learned about moments?
the force by the spring exert a moment on the rod equal to F*(half length of rod) ( the perpendicular distance for the line of action of the force and the rotation axis)
if i denote the rod L and F is kx then
the moment about the rotation axis , exerted by the spring is kx*0.5*L
 
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And what resists the moment exerted by the spring?
 
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  • #10
do you mean the screw at the center of the rod?
 
  • #11
Yossi33 said:
do you mean the screw at the center of the rod?
I think he meant the moment of inertia!
 
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  • #12
PeroK said:
I think he meant the moment of inertia!
Yes. So can you write an equation of motion using the moment exerted by the spring and the moment of intertia of the rod?
 
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  • #13
pbuk said:
Yes. So can you write an equation of motion using the moment exerted by the spring and the moment of intertia of the rod?
https://ibb.co/kgYgSL9 is it correct?

1647049718000.png
 
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  • #15
thank you all for the help
 
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