Recent content by Zacku

I will try other tests then. But just to specify that the histogram I showed is indeed a one sample histogram bu that contains 50000 points in it.

Hello everyone, I explain my problem: I have a set of histograms that do not appear normal (in the sense of the normal distribution). I need to convince a referee that it is in fact not normal. I have checked the skewness and the kurtosis and the former is at -2 and the latter is 60 ! I...

Hi, I am not sure I understand all your questions but about the capacitor you can't simply apply the superposition property from the result of two non-metallic isolated plates. If you have a plate capacitor with metallic plates, the resulting field inside the slit can be in principle...

Hi, The problem is that you try to apply the second principle of thermodynamics for the thermodynamic entropy to a configurational entropy for a binary mixture of macroscopic grains. There is no reason for your extension of the second principle to be true in general even though statistical...

So you have already, say, x(t), y(t) and z(t) as a function of the initial conditions and e,m and B?

Hi, I don't know if it's the most clever thing to do but at least you can try to solve the whole trajectory for one electron. I don't know if you already know how to do it but if not, can you write down Newton's second law of dynamics for the Lorentz force? That would be definitely a...

No you don't need the r^2dr part in the integral because your dipole has a fixed "length" and therefore its length shouldn't be taken as a degree of freedom. I don't know exactly the result but a sinh sounds good to me.

I have to say I didn't know about these vortices. I am not sure I understand the gradient term in Landau-Ginsburg equation 1 in you link or at least I am not sure that it disagrees with my previous statement. Since it is a term in \left|\left(-i \hbar \vec{\nabla} - \vec{A}\right) \psi...

Well the thing is that you should have \cos \theta instead of \cos \phi in the exponential. The reason for that is that you have an external field which point toward a non varying direction. In spherical basis and coordinates the only vector that fulfill this criteria is \hat{u}_z whose...

No because you are in 3D and the angular measure you have to use is sin \theta d\phi d\theta and not just d\theta.

Ok we speak about the same things :smile:. If you consider pre-field theory and pre-RG understanding well I can't really tell. I guess that first it failed to predict the good exponents and second, again in principle there is no real reason for the free energy to obey such an expansion...

Can you give an example of the type of Landau free energy you are talking about 'maybe I am also confusing with something else)? Considering what is wrong in Landau approach in principle even if one includes all the gradient he can? The problem is that it confuses the free energy of the...

Hi, The area under the graph is something like \int_0^Q V(q) dq Now if you decompose V(q) in something like U_1 - U_2 and express the integral as a virtual charging procedure in N steps. You will get that it is roughly the sum \sum_{i=1}^N qU_1(i)-qU_2(i) which is basically the total...

Hi, This sentence is just fine actually especially for a conceptual explanation without entering into technical and irrelevant details.

Hi, You have to compute the partition function first...do you know how to do that?