Recent content by zcdfhn
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Disproving Isomorphism of G/N & G'/N': Counterexample Needed
Prove or disprove: Suppose N is a normal subgp of G and N' is a normal subgp of G'. If G is isomorphic to G' and N is isomorphic to N' does that mean that G/N is isomorphic to G'/N'? I was trying to work out a proof until my professor told us to think of subgroups of the integers when doing...- zcdfhn
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- Normal
- Replies: 1
- Forum: Calculus and Beyond Homework Help
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Proving R/Q and Q/Z Has No Element of Finite Order
Thank you so much! You really clarified my view on quotient sets, I finally found a connection to what I learned about the quotient Z/nZ and it makes so much sense now.- zcdfhn
- Post #3
- Forum: Calculus and Beyond Homework Help
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Proving R/Q and Q/Z Has No Element of Finite Order
Prove R/Q has no element of finite order other than the identity. First of all, I have trouble visualizing what R/Q is. But I do know that afterwards you can try to raise an element in R/Q to a power to get to 0, but there will not be a finite number that will be able to do so except zero...- zcdfhn
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- Groups
- Replies: 2
- Forum: Calculus and Beyond Homework Help
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What Are the Quotient Groups of D6 and D9 Up to Isomorphism?
Thanks that's much clearer, so my approach to find all the quotient groups of D6 is to use the 1st isomorphism theorem, so I start with finding all the normal subgroups of D6, which are {id}, {id, R^2, R^4}, {id, R, R^2, R^3, R^4, R^5}, and D3, where R = rotation by pi/3 (I'm not sure if I'm...- zcdfhn
- Post #3
- Forum: Calculus and Beyond Homework Help
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What Are the Quotient Groups of D6 and D9 Up to Isomorphism?
Find, up to isomorphism, all possible quotient groups of D6 and D9, the dihedral group of 12 and 18 elements. First of all, I don't understand the question by what they mean about "up to isomorphism." Does this mean by using the First Isomorphism Theorem? Also does this question imply that...- zcdfhn
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- Groups quotient Quotient groups
- Replies: 4
- Forum: Calculus and Beyond Homework Help
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Graduate I was wondering what Q/Z, or the rational numbers modulo the integers.
Oh ok i think I get it, so rational numbers that are the same signed fractional distance from an integer are in the same coset of Q/Z?- zcdfhn
- Post #3
- Forum: Linear and Abstract Algebra
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Graduate I was wondering what Q/Z, or the rational numbers modulo the integers.
I was wondering what Q/Z, or the rational numbers modulo the integers. I am struggling to visualize what the cosets may be. Thank you for your time.- zcdfhn
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- Integers Numbers Rational
- Replies: 2
- Forum: Linear and Abstract Algebra
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Undergrad Two sets are isomorphic to each other
I think I had a moment of insight when I was learning about isomorphisms and I just need people to verify what I think I figured out. So I was thinking if two sets are isomorphic to each other does that mean ANY bijective function from one set to the other is an isomorphism? Thank you for...- zcdfhn
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- Sets
- Replies: 1
- Forum: Linear and Abstract Algebra
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Solving Rotational Dynamics of Mass M & R Rolling on Ramp at Angle θ
A uniform solid sphere of mass M and radius R rolls, without slipping, down a ramp that makes an angle θ with the horizontal. The question ask for me to find the force of friction between the ramp and the sphere. My attempt at the problem was to utilize the x-component of the force of gravity...- zcdfhn
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- Dynamics Rotational Rotational dynamics
- Replies: 2
- Forum: Introductory Physics Homework Help
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Group generated by a nonzero translation
A glide reflection composed with itself is a translation. And you get a glide reflection by composing a reflection with a translation.- zcdfhn
- Post #3
- Forum: Calculus and Beyond Homework Help
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Group generated by a nonzero translation
Let G1 be the group generated by a nonzero translation and G2 be the group generated by a glide reflection. Show that G1 and G2 are isomorphic. Here is how I started: G1 = <Tb> where b\in C and Tb(z) = z+b G2 = <ML \circ Tc> where c and L are parallel to each other. Let's define a function...- zcdfhn
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- Group Translation
- Replies: 3
- Forum: Calculus and Beyond Homework Help
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Proving g-Orbit of z is Invariant Under g
Suppose g\in Isom C, z\in C: Prove that the g-orbit of z is invariant under g. I just need some clarification on what this is asking for: 1.) Are we assuming that g is a group of the isometries of C under composition? 2.) To show invariance, would I only have to show that the g-orbit...- zcdfhn
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- Invariant
- Replies: 1
- Forum: Calculus and Beyond Homework Help
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Can non-zero translations be composed of two reflections in perpendicular lines?
I know M(z) = a(z-bar)+b, where |a| = 1 and a \neq 1, a(b-bar) + b = 0 and i also know M(z) = z0 + ei2\eta(zbar - z0bar)- zcdfhn
- Post #3
- Forum: Calculus and Beyond Homework Help
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Can non-zero translations be composed of two reflections in perpendicular lines?
Prove that every non-zero translation Tb is a composition of two reflections in lines which are perpendicular to the direction of vector b. Note: Tb(z) = z+b where z,b\inC My guess at how to start this is to assume b = rei\theta where r = |b| and \theta=arg b, so then the direction of b is...- zcdfhn
- Thread
- Replies: 3
- Forum: Calculus and Beyond Homework Help
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Cancellation property of addition of natural numbers
I have to prove that for all k,m,n \in N that if m+k = n+k, then m=n. The problem mentions that I must prove this by induction. I did the base case k = 0: If m+0 = n+0, by identity m=n. Then I attempt to show that m+1 = n+1 implies m=n, but I am stuck, I don't see how induction can be...- zcdfhn
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- Addition Natural Natural numbers Numbers Property
- Replies: 8
- Forum: Precalculus Mathematics Homework Help