Recent content by zhillyz

First image showing script and plot Second image where all I have done is slightly change the thickness and now the plot looks very weird. Final image showing the kind of plot I am expecting. Am I just doing something stupid as I can't see what is wrong/different between my equations and the...

Homework Statement \int_{0}^{2\pi} \dfrac{d\theta}{3+tan^2\theta} Homework Equations \oint_C f(z) = 2\pi i \cdot R R(z_{0}) = \lim_{z\to z_{0}}(z-z_{0})f(z) The Attempt at a Solution I did a similar example that had the form \int_{0}^{2\pi} \dfrac{d\theta}{5+4cos\theta} where I would change...

That is what I got if you convert to those units. Though the comparison against the experimental value in table 1 is unitless i.e. magnetic moment/nuclear magneton and the equation above gives you an answer in units of nuclear magneton(if you don't put in the number of mu_N and just leave it as...

Yes sorry the subshell is 0d3/2 also its total angular momentum is 3/2 not its spin which I said before. I continued studying on my own when I didnt get an answer and in case anyone is interested the answer (I think) would be to use this formula (derived from the first equation I mentioned...

Homework Statement Calculate the magnetic moment of the ground state of \,_{20}^{39}Ca. Compare to the experimental value in table 1. Homework Equations Nuclear Shell Model knowledge The Attempt at a Solution Well firstly the magnetic moment of the nucleus similar to the spin is...

Forgot to say that; q^{2}(z) = k^{2}n^{2}(z) - \beta^{2},\hspace{5mm} \beta = kn_{in}sin \theta_{in}, \hspace{5mm}k=\dfrac{2\pi}{\lambda} and the second order differential of E with respect to t is; \dfrac{\partial^{2} E}{\partial t^{2}} = -\omega^{2}\Psi(z)\exp^{i(\beta x-\omega t)}...

Homework Statement Derive from Maxwell's equations these Hill equations for 's' and 'p' mode waves; s\hspace{3mm} modes: E(r,t) = \Psi_{s}(z)e^{i(\beta x - \omega t)}y \\ \hspace{10mm}Hill\, Equation for\, \Psi_{s}(z)\\ \hspace{17mm} \dfrac{d^{2}\Psi_{s}(z)}{dz^{2}} +...

Ahh forgot to get rid of the x so that would mean k = 2pi*b/a. And for cases where a<<b then it is just 2pi*b?

Homework Statement A wave function is given by: \Psi (x) = a cos(2\pi x) + b sin (2\pi x) for\: x<0 \\ and\\ \Psi (x) = Ce^{-kx} for\: x>0 \\ Determine the constant k in terms of a, b and c using the boundary conditions and discuss the case a >> b. Homework Equations...

Like I said even if it is not what you meant it led me to get the answer provided by my lecturer. I am familiar with the fact there are improved equations that require using the 4 vectors of each quantity. I have not been taught these yet however and we may build up to it for next years particle...

SUCCESS v2 has equalled 0.645c and M0 has equalled 4.58m0. Both the answers provided. I can't thank you enough. Cheers!

So my equation would be the conservation of momentum, the one you have stated is the rest mass of incident and target particles equalling the rest mass of the composite? I think where I was getting confused was thinking that conservation of momentum would need to sum the kinetic and rest mass...

Sorry I still am not sure. I was starting to think I understood. Momentum would be \gamma v_{1}m_{0} = \gamma_{2} v_{2}M_{0} V1 could be worked out with equation for kinetic energy which shows gamma = 4. Kind of confused as to the next step :/.

I think I am starting to get it, the Momentum; -

Besides energy, momentum is conserved. A formula that contains both would be; E^{2} = p^{2}c^{2} + m^{2}c^{4} So total energy of the system equals the sum total of both particles rest mass plus the kinetic energy of the incident particle. The system after the collision must equal the same...