Ok let us expand out your expression above :
[SIZE="3"]
(pμξμ),λ\frac{∂(p_{v}η^{v})}{∂p_{λ}}−(pvηv),λ\frac{∂(p_{v}ε^{v})}{∂p_{λ}} =
( pμ,λεμ + pμεμ,λ ) ( ηλ + pv\frac{∂(η^{v})}{∂p_{λ}} ) -
( pv,ληv + pvηv,λ ) ( ελ + pv\frac{∂(ε^{v})}{∂p_{λ}} )
Now we have : \frac{∂(ε^{v})}{∂p_{λ}} = 0 =...