Master Vector Analysis with Expert Help: Proven Solutions to Common Problems

[R3DH34RT]

Need help on vector analysis :(

Guys, I need ur help please... Can u help me to answer these problems? I'm very confused...

1. Show that the vector Ai + Bj + Ck is normal to the plane which equation is Ax + By + Cz = D, where A, B, C, D are constants

2. n = 0.5i + 0.5j + 0.7071k is the unit-normal for plane A. b = 4i + 5j + 2k, c = 2i + 3j + k. Calculate the area of parallelogram project from b x c to plane A. Calculate components of vectors b and c that are parallel to plane A.

3. New right hand coordinate axes are chosen at the same origin with e1' = (2e1 + 2e2 + e3)/3 and e2' = (e1 - e2) x 1.4. Express e3' in term of e1. If t = 10e1 + 10e2 - 20e3, express t in terms of the new basis ek'. Express the old coordinate xi in term of xk' , xi = f(xk')

Please help me guys... :( Thanks a lot...

 

[EnumaElish]

What are the relevant equations? How do you define "normal"? What is a projection? How do you define "parallel"?

 

[R3DH34RT]

normal is perpendicular to the plane

 

[HallsofIvy]

What do you know about the inner product of two perpendicular vectors?

 

[R3DH34RT]

The inner product of 2 perpendicular vector is zero, right?
But, is there any relationship? :(

 

[mcampbell]

Do you have anymore information about D? What do you know about equations of a plane?

 

[R3DH34RT]

No, I don't have more information about D.
I think that's already the equation of a plane?
Thanks.

 

[D H]

Let \boldsymbol x_0 = (x_0, y_0, z_0) be some specific point on the plane. Let \boldsymbol x = (x, y, z) be any point on the plane. Can you write equations that describe the points \boldsymbol x_0 and \boldsymbol x? What is the inner product of the vector from \boldsymbol x_0 to \boldsymbol x with the vector \boldsymbol n = (A,B,C)?

 

[R3DH34RT]

D is just a constant.
The equation of a plane is should be the normal of the vector, right?

 

[R3DH34RT]

Do you mean (x-x0)/x + (y-y0)/y + (z-z0)/z = 0?
The inner product should be zero, right?

 

[D H]

Do you mean (x-x0)/x + (y-y0)/y + (z-z0)/z = 0?

No. Where did you get the division?

The inner product should be zero, right?

Yes, but this is what you need to prove.

Expanding on my previous post:

Let \boldsymbol x_0 = (x_0, y_0, z_0) be some specific point on the plane. Let \boldsymbol x = (x, y, z) be any point on the plane.

Because both \boldsymbol x_0 and \boldsymbol x are on the plane, Ax_0 +By_0+Cz_0 = D and Ax +By+Cz = D.

(1) What is the difference between these equations?

(2) What is the vector from \boldsymbol x_0 to \boldsymbol x?

You are given that \boldsymbol n = (A,B,C).

(3) What is the inner product between \boldsymbol n and the vector from \boldsymbol x_0 to \boldsymbol x?

Don't guess. Use the answer to question 2. Finally, relate the answers to questions 1 and 3.

 

[R3DH34RT]

The vector from x0 to x is (x-x0) right?
So should I do the inner product between (x-x0) . (n)?
Then I won't get any number, just some equation in x n x0?

 

[D H]

The vector from x0 to x is (x-x0) right?
So should I do the inner product between (x-x0) . (n)?

Yes. Do that. The reason for doing this is that the vector \boldsymbol x - \boldsymbol x_0 represents any arbitrary vector on the plane. If a vector is normal to every vector on some plane the vector is normal to the plane itself.

Then I won't get any number, just some equation in x n x0?

Please use English, not TXT-speak. Is it really that much harder to type x and x0?

 

[R3DH34RT]

OK... I'll do that...
Can you please help me with number 2 and 3?
Thanks :)

 

[R3DH34RT]

Hi, can anyone help me with the other question please...?
I am so depressed... :(
Need some hints... Thanks...

 

[D H]

Redheart, you really do need to show some work before most people here will help you.

 

[R3DH34RT]

I calculated the cross product of b x c, buat I don't know what is the meaning of "projection to plane A"

But for number 3, I can't figure out the meaning. Can you please give a hint?

Thanks...

 

[HallsofIvy]

Guys, I need ur help please... Can u help me to answer these problems? I'm very confused...

1. Show that the vector Ai + Bj + Ck is normal to the plane which equation is Ax + By + Cz = D, where A, B, C, D are constants

2. n = 0.5i + 0.5j + 0.7071k is the unit-normal for plane A. b = 4i + 5j + 2k, c = 2i + 3j + k. Calculate the area of parallelogram project from b x c to plane A. Calculate components of vectors b and c that are parallel to plane A.

3. New right hand coordinate axes are chosen at the same origin with e1' = (2e1 + 2e2 + e3)/3 and e2' = (e1 - e2) x 1.4. Express e3' in term of e1. If t = 10e1 + 10e2 - 20e3, express t in terms of the new basis ek'. Express the old coordinate xi in term of xk' , xi = f(xk')

Please help me guys... :( Thanks a lot...

I calculated the cross product of b x c, buat I don't know what is the meaning of "projection to plane A"

It tells you what to do in the next sentence: "Calculate components of vectors b and c that are parallel to plane A". Find the projection of b x c on the normal vector you found in 1, subtract it from b x c to find the part parallel to the plane.

But for number 3, I can't figure out the meaning. Can you please give a hint?

Thanks...

Are these new coordinate axes still orthogonal to one another? Check the inner product of e1' and e2' that you are given to make sure. Assuming they are orthogonal, then e3' must be orthogonal to both. How do you find a vector orthogonal to two given vectors? Of course, you have to be careful of the sign- this has to be a right hand coordinate system.

 

[R3DH34RT]

for number 3, I've found the e'3 vector which is 1/3 V2 e1 + 1/3 V2 e2 - 4/3 V2 e3, here V means the square root.
But I still don't know how to make it to ei part...?

 

[R3DH34RT]

I'm sorry, the question should be like this:
New right hand coordinate axes are chosen at the same origin with e1' = (2e1 + 2e2 + e3)/3 and e2' = (e1 - e2) x 1.4. Express e3' in term of ei (not e1, sorry...). If t = 10e1 + 10e2 - 20e3, express t in terms of the new basis ek'. Express the old coordinate xi in term of xk' , xi = f(xk')

 

[R3DH34RT]

Hello...? :(