Is Dirac's equation valid for point charges?

[what_are_electrons]

I've read that Dirac's equation for explaining spin does not hold if electrons are defined as true point charges. Is that correct?

 

[dextercioby]

WHATTTTTTTTTTTTTTTTTTTT?Hell,no.What said/wrote that was a big LIAR.

Daniel.

 

[quantumdude]

Dirac's equation is written for point charges, and there's nothing ill-defined about it.

What's the source of this statement?

 

[selfAdjoint]

Maybe he's worrying about self-action at zero distance?

 

[marlon]

Perhaps he is wondering about the fact that in QFT, the position of some particle is not exact and therefore you cannot point out exactly where the particle is. It is situated inside a little cloud, if you will, expressing the region where you have a certain propability to find such particle...Perhaps he is just referring to orbitals ?

marlon

 

[dextercioby]

Marlon,don't speculate & perform a bad tasting mixing of QM & QFT...
Let us allow the OP to come up with the source of missinformation...

Daniel.

 

[marlon]

Marlon,don't speculate & perform a bad tasting mixing of QM & QFT...
.

Err, how can you mix QM with QFT, dexter ?

marlon

 

[dextercioby]

U did that...Not me...If you're claiming that "orbitals" and QFT live happily ever after,then you're wrong...

Daniel.

 

[marlon]

U did that...Not me...If you're claiming that "orbitals" and QFT live happily ever after,then you're wrong...

Daniel.

So are you saying that the concept of orbitals does not exist in QFT ?

I hope not...

You do know that all the principles of QM are incorporated into QFT. I did not invent this (unfortunately), many other more "ingenious" minds did...

marlon

ps : and are you saying that uncertainty does not exist in QFT ?

 

[dextercioby]

UNCERTAINTY EXISTS IN QFT,ORBITALS NOT.That's (the second part,really) what i meant by mixing things...Concepts...

Daniel.

 

[marlon]

UNCERTAINTY EXISTS IN QFT,ORBITALS NOT.That's (the second part,really) what i meant by mixing things...Concepts...

Daniel.

Ok, then if orbitals do not exist in QFT, this implies that the spherical harmonics also don't exist in QFT. Are you really serious now ?

marlon

Let's not fall into a discussion on personal interpretations...stick to the physics...we might as well be discussing your favorite actor

 

[Hans de Vries]

I've read that Dirac's equation for explaining spin does not hold if electrons are defined as true point charges. Is that correct?

The Dirac's equation hasn't anything to do with this.


Observable spin effects like the spin angular momentum and the magnetic
momentum can not come from a spinning point charge. A spinning charge
with the classical electron radius (2.817940285 10^-15 meter) is also much to
small to support the measured values.

To get for instance the measured magnetic moment at this radius means
that the charge needs to "rotate" with a speed much higher than the speed
of light.

If we use classical equations to get an indication of the required size then
it turns out that one gets more realistic values (\leq c) if you assume a "radius"
of circa 137 times the classical electron radius: ~ 3.8616 10^-13 meter, where
1/137.03599911 is the finestructure constant.


You get this radius if you apply Heisenbergs Uncertainty Principle:
Take the electron's rest energy of 0.5109892 MeV as the uncertainty in
energy. This corresponds with an uncertainty in momentum of 0.5109892
MeV/c.

Now if you use the equation: \Delta x \Delta p \ = \ \hbar then you'll get the radius above
of ~ 3.8616 10^-13 meter as the uncertainty in position. The corresponding
rotation frequency becomes \approx the 1.235 10²⁰ Hz: The rest frequency of
the electron.

In a similar way one can obtain the Bohr Radius and the ground state
frequency of the hydrogen atom from the orbital angular momentum and
the 13.6 eV ionisation energy of the ground state.


So to conclude:

Spin and orbital angular momentum as well as the spin and orbital
magnetic momentum are in "the wave" and not in "the particle"



Regards, Hans

 

[dextercioby]

Ok, then if orbitals do not exist in QFT, this implies that the spherical harmonics also don't exist in QFT. Are you really serious now ?

marlon

Let's not fall into a discussion on personal interpretations...stick to the physics...we might as well be discussing your favorite actor

It's just that.Personal interpretations... To me,"orbital(s)" is a term not pertaining to QM,but to chemistry and their idea of "doing" QM.It's very deluding.It derives from "orbit" and hence the old theory of Bohr.No respectable physicst teaching QM would not use this word...I think chemistry teachers have created a "passion" for it...

If u saw a QM course mentioning the term "orbital",then the author was not a physicist...Was a moron...



Daniel.

 

[quantumdude]

The Dirac's equation hasn't anything to do with this.

Since the original poster hasn't explained the remark, it's not really possible to say. Dirac's equation does indeed describe the mechanics of spin-1/2 point particles. If we take the OP at face value, it says that there is some problem with that description. What you have explained is why classical spinning cannot be the same as quantum mechanical spin.

 

[marlon]

It's just that.Personal interpretations... To me,"orbital(s)" is a term not pertaining to QM,but to chemistry and their idea of "doing" QM.It's very deluding.It derives from "orbit" and hence the old theory of Bohr.No respectable physicst teaching QM would not use this word...I think chemistry teachers have created a "passion" for it...

If u saw a QM course mentioning the term "orbital",then the author was not a physicist...Was a moron...



Daniel.

I am sorry but what you say is wrong. Orbitals are just the squared spherical harmonics. They are nothing else then a probability...But why orbitals, well, because these spherical harmonics are the eigenfunctions of the equations for L² and L_z...They only depend on the two angular degrees of freedom. This combined with the name of L² and L_z, you have the explanation for the word ORBITAL... Nothing is orbiting here

marlon

 

[Hans de Vries]

Since the original poster hasn't explained the remark, it's not really possible to say. Dirac's equation does indeed describe the mechanics of spin-1/2 point particles. If we take the OP at face value, it says that there is some problem with that description. What you have explained is why classical spinning cannot be the same as quantum mechanical spin.

Classical spinning isn't quantum mechanical spin OK. But the gap is not
that big. Dirac included Pauli spinors in his equation to account for the
spin 1/2 behavior. It was the (relativistic) classically derived Thomas
Factor of 2 which convinced Pauli of the existence of the electron spin.
Tomonaga showed that this approach predicts other angular interactions
and energy levels in the atom as well.

The conclusion remains the same: spin angular and magnetic moment
can not stem from an arbitrary small sized particle. It must come from
the quantum field.

Regards, Hans

 

[quantumdude]

Classical spinning isn't quantum mechanical spin OK. But the gap is not that big.

Yes it is that big. It's huge, in fact. Take a spin-1/2 particle and rotate it through 2π radians. You'll find that you do not arrive at the initial state, but rather the negative of the initial state. Something is very much at odds with classical angular momentum here.

Dirac included Pauli spinors in his equation to account for the
spin 1/2 behavior.

Dirac included Dirac spinors (4 components) in his equation. They aren't the same as Pauli spinors, which have 2 components. And I don't think it's accurate to say that he included them to account for spin-1/2 particles. The mapping of Dirac's theory to spin-1/2 particles emerges naturally from the linearization process on the relativistic Hamiltonian, if we take the gamma matrices to be of the lowest possible dimension.

It was the (relativistic) classically derived Thomas
Factor of 2 which convinced Pauli of the existence of the electron spin.
Tomonaga showed that this approach predicts other angular interactions
and energy levels in the atom as well.

How does this address the fitness of the Dirac equation with point charges?

The conclusion remains the same: spin angular and magnetic moment
can not stem from an arbitrary small sized particle. It must come from
the quantum field.

In QFT the particles are excitations of the quantum field, and they carry angular momentum (including spin). So it's not surprising that angular momentum must come from the quantum field. But we weren't talking about where angular momentum comes from, we were talking about an alleged problem with the Dirac equation.

 

[what_are_electrons]

I've read that Dirac's equation for explaining spin does not hold if electrons are defined as true point charges. Is that correct?

Physics Prof. I.A.Sellin (Univ of Tenn.) wrote a section (p 17-32) titled "Atomic Structure and Spectra" in a 1988 book called " Spectroscopy Source Book" published by McGraw Hill. On p23 he wrote: "A spinning electron can crudely be pictured as a spinning ball of charge, imitating a circulating electric current (though Dirac electron theory assumes no finite electron radius - classical pictures fail.) This circulating current gives rise to a magnetic field distribution very similar to that of a small bar magnet, with north and south magnetic poles symmetrically distributed along the spin axis above and below the spin equator."

On page 31 he goes on to write: "Since in Maxwell's theory, only accelerating charges radiate, atomic electrons in stationary states do not immediately collpase into the nucleus. Their freedom from this catastrophe can be interpreted as a proof that electrons may NOT be viewed as pointlike planetary objects orbiting atomic nuclei."

"There is still no generally accepted explanation for why electrons do NOT explode under the tremendous Coulomb repulsion forces in an object of small size."


Robert Gourian worte a book in 1967 titled "Particles and Accelerators" (World Univ Libr). On p.27 of this book he wrote: "The electron cannot be considered as a geometric point which is a perfect conception of zero, for its electric field would then be infinite. But if it is slightly extended the electric charge tends to repel itself, and would lead to dissolution unless a contrary force opposed it in order to maintain cohesion; but this 'self-force' could only accumulate an infinite self-energy, giving to the electron infinite mass!"

In the same book on p. 112 in a section titled "Parity and its 'non-conservation', Gourian wrote: "The free electron only exists in a non-symmetrical form."


In a book written by Malcolm MacGregor (recently retired from LLNL) called "The Enigmatic Electron" published by Kluwer in 1992, he quoted Gottfried and Weisskopf book called "Concepts of Particle Physics Vol 1": "At one time it (the Dirac Equation) was thought to 'explain' the spin s=1/2 of the electron, but we now know that this is not so. Equations of the Dirac type can be constructed for any S. At this time we have no understanding of the remarkable fact that the fundamental fermions of particle physics (electrons, neutrinos, quarks, etc.) all have spin 1/2."

MacGregor then wrote: " Although the electric charge e of the electron, as viewed in scattering experiments, seems to be point-like, its manifestation in atomic bound states is NOT point-like. The Lamb shift reveals that the electric charge is smeared out over a region of space which is comparable to the electron Compton radius R(c) as we discuss in Chapter 7. This smearing out is attributed to two characteristic phenomena of QED: vacuum polarization, which broadens the electric field of the charge; and zitterbewegung, which broadens the spatial location of the charge. Thus we have an effective electron bound-state QED charge radius

R(QED) approx = R(C). "


These quotes are the reason that I wrote the question: I've read that Dirac's equation for explaining spin does not hold if electrons are defined as true point charges. Is that correct?

 

[Kane O'Donnell]

What the passages you've quoted seem to be alluding to is the fact that you can't consider an electron as a *classical* point particle.

Kane

 

[what_are_electrons]

What the passages you've quoted seem to be alluding to is the fact that you can't consider an electron as a *classical* point particle.

Kane

Yes, quite correct. If my reading and comprehesion are correct, then Dirac first developed his equation(s) for an electron that was understood to be a point charge, be it a classical point charge or a quantum point charge.

 

[Kane O'Donnell]

No, Dirac didn't do that. What he did was try and come up with a relativistic wave equation for a quantum mechanical point charge. The fact that QM changes one's ideas of position and so forth were getting to be fairly well known back then, so you would expect that Dirac knew that classical point charges were not going to come out of his equations (especially since the NR limit needed to be something like the Schrodinger equation).

Kane

 

[Hans de Vries]

Yes it is that big. It's huge, in fact. Take a spin-1/2 particle and rotate it through 2π radians. You'll find that you do not arrive at the initial state, but rather the negative of the initial state. Something is very much at odds with classical angular momentum here.

Quantum mechanical spin and orbital angular momentum (both from
spin ½ and spin 1 particles) can be transferred to macroscopic
particles where it behaves like ordinary angular momentum (Einstein,
de Haas, Dublin). You are talking about a specific property of spin
½ particles.

Dirac included Dirac spinors (4 components) in his equation. They aren't the same as Pauli spinors, which have 2 components. And I don't think it's accurate to say that he included them to account for spin-1/2 particles.

Dirac’s original 4x4 matrices are build from 2x2 Pauli spinors on the
diagonal Dirac already mentions Pauli’s spin theory in the introduction
of his paper. Pauli's spin theory was a 2x2 matrix version of the
Shroedinger equation using his spinors.

Pauli spinors obey Heisenberg’s matrix mechanics angular momentum
commutation rules:

s_xs_y-s_ys_x = is_z, s_ys_z-s_zs_y = is_x, s_zs_x-s_xs_z = is_y

and in particular for spin ½ particles:

|s|² = ½ ( ½ + 1 ) = ¾

with: s_x \ = \ \frac{1}{2}\sigma_x, \ \ \ \ \ s_y \ = \ \frac{1}{2}\sigma_y, \ \ \ \ \ s_z \ = \ \frac{1}{2}\sigma_z

The mapping of Dirac's theory to spin-1/2 particles emerges naturally from the linearization process on the relativistic Hamiltonian, if we take the gamma matrices to be of the lowest possible dimension.

Pauli had already proposed a 2x2 matrix version of the Schroedinger
equation using his spinors. Historically it's hard to say in which order
Dirac arrived at his equation. Did he linearized Klein Gorden while playing
with Pauli's work or not? while trying to do with Klein Gorden's equation
what Pauli did with Schroedinger's equation to include spin...

Two of the requirements for linearization:

\gamma_m^2 = 1, \ \ \ \gamma_m \gamma_n + \gamma_n \gamma_m = 0

are also fulfilled by Pauli's Spinors:

\sigma_m^2 = 1, \ \ \ \sigma_m \sigma_n + \sigma_n \sigma_m = 0

Dirac must have seen this immediately, probably to find out that he
needed to combine them in a 4x4 representation to get things right.
(There are only 3 spinors and you need 4 gamma's. That's why a
4x4 representation is needed)

How does this address the fitness of the Dirac equation with point charges?

Dirac’s equation doesn’t have any reference to any presumed size of the
electron. It’s therefor incorrect to say that it doesn’t work for a certain size.

In QFT the particles are excitations of the quantum field, and they carry angular momentum (including spin). So it's not surprising that angular momentum must come from the quantum field. But we weren't talking about where angular momentum comes from, we were talking about an alleged problem with the Dirac equation.

The background of the presumed problem was not given so I could only
guess where the misunderstanding came from. It may as well come from
the first of the two quotes from the paper:

"The question remains as to why Nature should have chosen this
particular for the electron instead of being satisfied with the point charge"

However, in a second quote he uses the word "point charge" again but
now in combination with his equation:

"It appears that the simplest Hamiltonian for a point-charge electron
satisfying the requirements of relativity and the general transformation
theory leads to an explanation of all duplexity phenomena without further
assumption."


Regards, Hans

 

[what_are_electrons]

I need to ask 2 more questions. (1) Do bound electrons inside a normal atom (excluding Z=1) have a finite charge based size on the order of 10(-13) cm? (2) What is the size of charge of an electron after it is free from an atom?

 

[dextercioby]

I need to ask 2 more questions. (1) Do bound electrons inside a normal atom (excluding Z=1) have a finite charge based size on the order of 10(-13) cm?

We don't really know the SPATIAL extent of the electrons and we could never find out,at least as long as QM and its principle of uncertainty is among us...

(2) What is the size of charge of an electron after it is free from an atom?

The same kinda question gets the same answer...

Daniel.

 

[Hans de Vries]

I need to ask 2 more questions. (1) Do bound electrons inside a normal atom (excluding Z=1) have a finite charge based size on the order of 10(-13) cm? (2) What is the size of charge of an electron after it is free from an atom?

I should first say that the only "official size" here is probably the size of the
electron's wave-function cloud in the atom. (in the order of 10^-10 meter)
The other sizes are "interesting to know" but should be viewed in the light of
the presumptions to derive them.

Regards, Hans

 

[what_are_electrons]

We don't really know the SPATIAL extent of the electrons and we could never find out,at least as long as QM and its principle of uncertainty is among us...

The same kinda question gets the same answer...

Daniel.

If I understand correctly, then a lot of people are wasting their time trying to determine the size of an electron because of the mandates of QM theory. Is that right?

 

[what_are_electrons]

I should first say that the only "official size" here is probably the size of the
electron's wave-function cloud in the atom. (in the order of 10^-10 meter)
The other sizes are "interesting to know" but should be viewed in the light of
the presumptions to derive them.

Regards, Hans

I understand what you've written, but I still seek a bit more info and pose the following question:

If a free electron were indeed to have a comparatively small size on the order of 10^-15 meter, then I hope to understand how an electron wave-function cloud, that is on the order 10^-10 meter, can gather all its matter away from its "highly" dispersed atomic state and "condense" itself into a particle that is 10⁺⁵ times smaller as it escapes from (or is forced out of) the atom and becomes a free electron.

 

[what_are_electrons]

Isn't it strange that we know the size of a proton and a neutron is about 0.8 Fermis and that we've been working with electrons for about 200 years and we still don't know the size of the electric field or the magnetic field of a free or a bound electron?

I guess the HUP doesn't apply to protons or neutrons.
What do you say?

 

[dextercioby]

The HUP aplies to all particles,without discrimination...The figures for "radii" of elementary particles are very "doubtful"...

Daniel.

 

[Kane O'Donnell]

I hope to understand how an electron wave-function cloud, that is on the order 10-10 meter, can gather all its matter away from its "highly" dispersed atomic state and "condense" itself into a particle that is 10+5 times smaller as it escapes from (or is forced out of) the atom and becomes a free electron.

The probability cloud of an electron is not an accurate measure of size - the cloud is a graphical depiction of the probability of finding a (*point*) charge at each location in space. It does not reflect the size of an electron - as has already been stated, in quantum mechanics, as in classical physics, idealised particles are treated as having *no* spatial extent. So far, there is no experimental evidence as far as I am aware showing that the electron deviates from this treatment.

On the other hand, we know that protons and neutrons *do* have internal structure, and hence do deviate from being point particles. It's not a question of whether the uncertainty principle applies - it's just that we have evidence showing that protons, for example, aren't point-like objects, whereas we don't for an electron.

Cheerio,

Kane

 

[what_are_electrons]

Possible "Sizes" of Electron

M. MacGregor's (LLNL) book "The Enigmatic Electron" and the book edited by D. Hestenes and A. Weingartshofer (1991) "The Electron: New Theory and Experiment" discuss much of the most modern understanding of the electron.

MacGregor's book discusses electric size and magnetic size in various terms, including:
a. R(c) = Compton radius = 3.86x10(-11) cm
b. R(QMC) = quantum mechanical Compton radius = 6.69x10(-11) cm
c. R(alpha-QMC) = QED corrected QMC radius = 6.70x10(-11) cm
d. R(E) = radius of the electric charge on the electron = <10(-16) cm
e. R(QED) = observed QED charge distribution for a bound electron = approx. R(c)
f. R(0) = classical electron radius = 2.82x10-13 cm
g. R(H) = magnetic field radius = >4x10(-12) cm

MacGregor's book is a kind of treasure for me and my interests.

 

[sifeddin]

I am sorry but what you say is wrong. Orbitals are just the squared spherical harmonics. They are nothing else then a probability...But why orbitals, well, because these spherical harmonics are the eigenfunctions of the equations for L² and L_z...They only depend on the two angular degrees of freedom. This combined with the name of L² and L_z, you have the explanation for the word ORBITAL... Nothing is orbiting here

marlon

... and the player in the blue corner "wins" the match against the green "thing"
Sorry couldn't help it.

 

[marlon]

Thanks sifeddin

regards
marlon

 

[dextercioby]

Marlon,it's funny as hell... He couldn't even spell the word properly..."WINS"...

Daniel.

 

[marlon]

Politeness

Marlon,it's funny as hell... He couldn't even spell the word properly..."WINS"...

Daniel.

Dextercioby,
I really don't think it is the intention of this forum to make fun of people or their posts. Everybody makes spelling-mistake, yes even you.

Please, again i ask you : do try to be more polite. You are NOT being funny right now and stop arguing with everybody.

Let us just stick to the physics alright ?

marlon

 

[dextercioby]

I believe it was't you the person to whom i was referring to...I don't understand why you did stand up for him...A lawyer physicst...

I found that reply a bit "annoying",just as u did with mine...So i reacted...

Daniel.

 

[sifeddin]

I need to ask 2 more questions. (1) Do bound electrons inside a normal atom (excluding Z=1) have a finite charge based size on the order of 10(-13) cm? (2) What is the size of charge of an electron after it is free from an atom?

Let me add to your questions my own quote from https://www.physicsforums.com/showthread.php?t=59739

An easy question to answer: I doubt! However, I subscribe to your transaction.
Yet could you just give a link, or any documented reference to what you said and why the electron "should" be a "point" particle; because I only got this as "talkings"
BTW if you know the origin of the word "lepton" give me a hint. Any one but "dextercioby" is welcome to answer.

I was waiting however for some knowlegable man like Kane O'Donnell to write such a thing as the word "point" so that to ask him to "reply with some references", preferabally online documents, and whether that Born who said that first or who?

 

[sifeddin]

If I understand correctly, then a lot of people are wasting their time trying to determine the size of an electron because of the mandates of QM theory. Is that right?

If you bother reading for dextercioby do not bother replying. He "seems" to stick with the stuff he learned in his "nowadays" courses and do not try to renew or even reform. (I corrected the verb according to his remark as a positive reaction to his note. but I will NOT reply to his nonsense or even good, though very rare, responses)

BTW very good depate between Hans de Vries and Tom Mattson.

I'm sorry here (again) because I elongate the thread with non-educative response much like "dextercioby's".

 

[quantumdude]

Everyone knock it off before I start putting the smack down.

 

[masudr]

Hear, hear. Keep it to the physics people.

About the relation between the Pauli spin matrices and the \gamma-matrices appearing in Dirac's equation. We can derive Dirac's equation as an attempt to replace the classical definition of energy with the relativistic definition and then linearize the equation (as Tom says). It can be shown that these matrices are elements of a Clifford algebra, and they can be derived completely independently of Pauli spin matrices.

I would go through the derivation from memory (I would also give the definition of a Clifford algebra), except that my memory cannot remember it too well. If I find it somewhere or if it comes back to me, I'll put it up.

Edit: I realized that this message didn't really contribute much to the discussion. Maybe I should look up the Dirac equation derivation and show that it can be done without any reference to the spin matrices.

 

[sifeddin]

Shut up! and Think! Theorize! then Calculate!

Everyone knock it off before I start putting the smack down.

I'm in the Phyisics corner Reff.
Would you care to join me and try answering my questions? (just look one post before the one you replied to ), I guess these questions are of the kind of the Unspeakable . Would some Physics Master like yourself would step up for such couragous movement. My hopes are great for you Reff.

 

[hypermorgan]

I think Dirac's Equation just describes the point particles.

 

[selfAdjoint]

The classical Dirac equation describes point particles. However the physics of the electron (at this level of energy) is descibed by the QUANTIZED Dirac equation. Now read what Urs Schreiber has posted today about quantized strings: https://www.physicsforums.com/showthread.php?p=448253#post448253; it applies to particles too. Because of uncertainty, any measurement on an electron will be smeared out. You can't get away from that. There isn't any hard lower limit, but the closer you get to a point's position, the more you lose control of the momentum.

 

[marlon]

great explanaition by Urs indeed

Thanks sA

regards
marlon

 

[what_are_electrons]

Yes, it is CURRENTLY difficult to measure the "diameter" of the electric charge, but maybe the question at hand is better restated as:

Why is it currently difficult to measure the size of an electron "accurately"?
Is it because the HUP tells us it is "effectively impossible" because the electron "appears" to our current measuring tools to be smeared out, or is it because the experimental physicists don't "yet" have the experimental tools or a suitable experimental design to achieve this difficult task and to put a better answer to the question of size?

 

[dextercioby]

Why is it currently difficult to measure the position or momentum "accurately"?
Is it because the HUP tells us it is "effectively impossible"

Yes...

or is it because the experimental physicists don't "yet" have the experimental tools or a suitable experimental design to achieve this difficult task and to put a better answer to the question of size?

No,even if,by absurd,they had the tools,they simply couldn't...measure the coordinate along an axis and the momentum along the same axis with ARBITRARY PRECISION AT THE SAME MOMENT OF TIME...

Daniel.

 

[sifeddin]

Yes...

No,even if,by absurd,they had the tools,they simply couldn't...measure the coordinate along an axis and the momentum along the same axis with ARBITRARY PRECISION AT THE SAME MOMENT OF TIME...

Daniel.

I guess the HUP doesn't apply to protons or neutrons.
What do you say?[/QUOTE]

dextercioby or Daniel:
No sarcasm,but really I wish you can read, search, think and take a little time before throwing away your rushed answer to some deep question. Didn't you think that doing such a thing may prevent more deep thinking people from answering a beautiful and mind relief answer. I wish you all the best with physics.

Anyway I saw it somewhere on the net that there is some kind of agreed numbers (with accuracy digits) for the diameter of the proton and the neutron but no such agreement yet (as stated earlier in this thread) for the electron. So why do you think experimental physicists could do this for some particles and not he electron if you are "certain" the the uncertainty principle applies equally to all particles. I will try to upload the link to the page with these particle diameters later or you can search for yourself so that you may find more than I found.

Nevertheless I began to believe that the really good questions posted on this forum specially and anywhere else are left unanswered for one reason or another. Then I really do not expect to see any answers to this question or the ones I posted earlier. Yet I will still hang around.

 

[sifeddin]

The probability cloud of an electron is not an accurate measure of size - the cloud is a graphical depiction of the probability of finding a (*point*) charge at each location in space. It does not reflect the size of an electron - as has already been stated, in quantum mechanics, as in classical physics, idealised particles are treated as having *no* spatial extent. So far, there is no experimental evidence as far as I am aware showing that the electron deviates from this treatment.

On the other hand, we know that protons and neutrons *do* have internal structure, and hence do deviate from being point particles. It's not a question of whether the uncertainty principle applies - it's just that we have evidence showing that protons, for example, aren't point-like objects, whereas we don't for an electron.

Cheerio,

Kane

Kane:
would you take few minutes to reply to my earlier questions and make me believe in this forum again.

I need to ask 2 more questions. (1) Do bound electrons inside a normal atom (excluding Z=1) have a finite charge based size on the order of 10(-13) cm? (2) What is the size of charge of an electron after it is free from an atom?

Let me add to your questions my own quote from https://www.physicsforums.com/showthread.php?t=59739

An easy question to answer: I doubt! However, I subscribe to your transaction.
Yet could you just give a link, or any documented reference to what you said and why the electron "should" be a "point" particle; because I only got this as "talkings"
BTW if you know the origin of the word "lepton" give me a hint.

I was waiting however for some knowlegable man like Kane O'Donnell to write such a thing as the word "point" so that to ask him to "reply with some references", preferabally online documents, and whether that Born who said that first or who?

 

[dextercioby]

I guess the HUP doesn't apply to protons or neutrons.
What do you say?

What??Please infer me to an "illuminating source" where i can learn that this fundamental logical consequence of the Postulates of QM (and by extension,the Postulates themselves) is/are not valid...
Does it mean that I've spent a year of my life learning something which is not correct?

Then i should kill my QM teacher...

Daniel.

 

[masudr]

The electron is treated as a point particle. We have the HUP which applies to all systems. Hence if we have some knowledge of the momentum, we can put a definite upper limit on the variance of the system's position. This is not the same thing as size.