Find the equation of the tangent to the curve

[footprints]

Find the equation of the tangent to the curve y=x^3-7x^2+14x-8 at the point where x = 1. \text{Answer: }y = 3x -3
Find the x-coordinate of the point at which the tangent is parallel to the tangent at x = 1.

I need help on the second part.

 

[arildno]

Well, let x* be the point you seek.
What do you know of x*?
Do you agree that we must have y'(x*)=3?
That is, the derivatives of y(x) must be equal at x=1 and x=x*

 

[footprints]

Do you agree that we must have y'(x*)=3?

Yes.

That is, the derivatives of y(x) must be equal at x=1 and x=x*

I think I get it. But I still don't know how to get the answer.

 

[arildno]

Well, do you agree that what you need to solve is the equation (written with "x"):
3=3x^{2}-14x+14
This can be rewritten as:
3(x+1)(x-1)-14(x-1)=0\to(3(x+1)-14)(x-1)=0
What must then x* be?

 

[footprints]

Oh! Thank you!