Writing Question (Position-Time Graph)

  • Thread starter Thread starter ihatephysics
  • Start date Start date
  • Tags Tags
    Graph Writing
Click For Summary
Average velocity on a position-time graph is determined by the slope of the line connecting two points, calculated as the change in position divided by the change in time. Instantaneous velocity is found by determining the slope of the tangent line at a specific point on the graph. This process involves identifying two points close to the desired point to approximate the slope. A practical method for finding the tangent line involves using a mirror to visually align with the curve at the point of interest. Understanding these concepts is essential for analyzing motion in physics.
ihatephysics
Messages
3
Reaction score
0
How can you find average velocity from a position-time graph? How can you find instantaneous velocity from a position-time graph?

Any help is appreciated!
 
Physics news on Phys.org
The velocity on a position-time graph is equal to the slope, so the average velocity is equal to the average slope.

The instantantaneous velocity on a position-time graph can be found by finding the slope of the line tangent to the graph at the instance of time in question.
 
A little expansion on kreil's post: Choose two points on the graph. Subtract the "x-coordinates" (change in position), subtract the "t-coordinates" (change in time) and divide the first by the second,
\frac{\Delta x}{\Delta t}[/itex] <br /> is the slope of the line and the average velocity. To find the instantaneous velocity, find the slope of the tangent line. Finding the tangent line itself is harder (and is why Newton and Leibniz get so much press!). When I was in school, we did this: take a small mirror and put it across the graph at the point at which you want to find the tangent line. Turn the mirror on that point until the graph seems to flow smoothly into its image (no &quot;corner&quot;). Use the mirror as a straightedge to draw a line there. That line is perpendicular to the curve. Now do the same to draw a line perpendicular to the perpendicular. That line will be the tangent line.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 9 ·
Replies
9
Views
430
  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 2 ·
Replies
2
Views
854
  • · Replies 6 ·
Replies
6
Views
955
  • · Replies 3 ·
Replies
3
Views
2K
Replies
25
Views
2K
  • · Replies 13 ·
Replies
13
Views
3K