What is the Origin of the Repelling Force Between Dark Energy and Matter?

[ax3111]

Okay so dark energy repels mass, but why is that? The reason why masses repel other masses when brought together is the electromagnetic force, but dark energy also doesn't interact at all with electromagnetic waves, and if it exhibited electromagnetic force it would interact with electromagnetic waves, so then, what is the repelling force of dark energy and matter? Is it quantifiable? Where does it come from? etc...

 

[mathman]

Dark energy force is anti-gravity. It has nothing to do with electromagnetic. DE according to current ideas (subject to change) is related to the concept of a cosmological constant in general relativity.

 

[ax3111]

does that mean the repelling force of dark energy is equal to that of the force of gravity?

 

[AC130Nav]

Okay so dark energy repels mass, but why is that? The reason why masses repel other masses when brought together is the electromagnetic force, but dark energy also doesn't interact at all with electromagnetic waves, and if it exhibited electromagnetic force it would interact with electromagnetic waves, so then, what is the repelling force of dark energy and matter? Is it quantifiable? Where does it come from? etc...

Dark Energy and Dark Matter are a patch on physics theories based on mathematics that have failed--new epicycles.

 

[Niznar]

If I understand it correctly (and I don't think I do), dark energy is not related to any forces, such as gravity or the electromagnetic force. It's thought to be a property of the universe itself, in essence the "fabric" of space-time stretching itself out due to quantum fluctuations. So there isn't really a "repelling force" in the sense I think you mean, since its not a force that acts on matter, but rather its what drives the universe to expand.

 

[bapowell]

Dark Energy and Dark Matter are a patch on physics theories based on mathematics that have failed--new epicycles.

The only thing dark matter and dark energy have in common is the word 'dark' and the fact that crackpots like to discount their existence without giving any tenable arguments.

 

[bapowell]

The simplest way to model dark energy in general relativity is to hypothesize a smooth energy component of the universe that has a negative pressure (quantum vacuum energy has this property). When this type of energy is used as the source in Einstein's equations, one obtains an isotropic and homogeneous universe that expands at an accelerated pace. So, it's not that individual masses are repelling each other; it's that the spacetime itself is expanding (much like ordinary non-accelerated expansion, only that this rate of expansion is itself increasing), and individual masses 'repel' each other as a result of the the expanding space between them.

So, accelerated expansion should be thought of as a gravitational effect of dark energy.

 

[Ich]

So, it's not that individual masses are repelling each other; it's that the spacetime itself is expanding (much like ordinary non-accelerated expansion, only that this rate of expansion is itself increasing), and individual masses 'repel' each other as a result of the the expanding space between them.

I think it's absolutely valid to say that dark energy is the source of repulsive gravity and thus repels matter. It doesn't "catalyse" masses to repel each other.

 

[bapowell]

I think it's absolutely valid to say that dark energy is the source of repulsive gravity and thus repels matter. It doesn't "catalyse" masses to repel each other.

...so we agree?

 

[Ich]

...so we agree?

Do you think our statements are the same?

 

[bapowell]

I have no idea. I agree that dark energy sources repulsive gravity; but test masses do not. The universe accelerates whether the test masses are present or not. If they are, then I guess it appears as if they are repelling each other, but really they are comoving with the expansion. I was trying to move away from the thinking that dark energy makes a kind of repulsive Newton's law possible for test masses -- it doesn't.

 

[Ich]

I agree that dark energy sources repulsive gravity; but test masses do not.

Yes, we agree on that. That's why I didn't understand your "individual masses 'repel' each other as a result of the the expanding space between them". Not the test masses repel each other, nor does DE make them repel each other. DE repels them.

I was trying to move away from the thinking that dark energy makes a kind of repulsive Newton's law possible for test masses -- it doesn't.

But you agree DE acts like kind of a negative matter density in the Newtonian sense? Just like a positive matter density attracts test masses, a negative one repels them.

 

[ax3111]

So basically what you guys are saying is that this "dark energy" is actually the expansion of spacetime as a biproduct of quantum fluxuations? Does this mean that the amount of dark energy is uniform across all of space? And if it is just the stretching of spacetime, then how is it that we can put a value of "how much" dark energy there is in space?

 

[bapowell]

So basically what you guys are saying is that this "dark energy" is actually the expansion of spacetime as a biproduct of quantum fluxuations? Does this mean that the amount of dark energy is uniform across all of space? And if it is just the stretching of spacetime, then how is it that we can put a value of "how much" dark energy there is in space?

Yes, that's one way to think of it. Quantum fluctuations are the right kind of stress energy for driving accelerated expansion, and are a candidate for dark energy. In this case, the dark energy would be perfectly uniform across space (a cosmological constant, if you will). In other models, in which the dark energy is the vacuum energy of a dynamical scalar field, the dark energy is time dependent and spatially homogeneous modulo quantum fluctuations of the field.

Using the equations that govern the homogeneous and isotropic expansion of the universe, it is possible to relate the expansion rate (by way of the Hubble parameter, H) to the energy density of the universe. In this way, 'more' dark energy results in a more rapid expansion.

 

[ax3111]

I'm sorry but I understood basically every other word you said. according to how much I do understand, you say that quantum fluctuations create stress energy, wouldn't this energy actually cause matter to contract towards one another? (because of the whole gravity thing..)

 

[bapowell]

I'm sorry but I understood basically every other word you said. according to how much I do understand, you say that quantum fluctuations create stress energy, wouldn't this energy actually cause matter to contract towards one another? (because of the whole gravity thing..)

No, this is precisely where the antigravity comes in. Quantum fluctuations have a negative pressure, as opposed to more ordinary items like radiation, which have positive pressure. The negative pressure leads to a repulsive, accelerated expansion of spacetime.

 

[George Jones]

But you agree DE acts like kind of a negative matter density in the Newtonian sense? Just like a positive matter density attracts test masses, a negative one repels them.

The weak-field limit of Einstein's equation without cosmological constant/dark energy leads to Poisson's equation,

\nabla^2 \Phi = - \vec{\nabla} \cdot \vec{g}= 4 \pi G \rho,

where \Phi is gravitational potential and \vec{g}= - \vec{\nabla} \Phi is the acceleration of a small test mass.

The weak-field limit of Einstein's equation with cosmological constant/dark energy \Lambda leads to a modified "Poisson" equation,

\nabla^2 \Phi = 4 \pi G \rho - \Lambda c^2.

For a spherical mass M, the divergence theorem applied to the above gives

\vec{g} = \left(-\frac{GM}{r^2} + \frac{c^2 \Lambda}{3} r \right) \hat{r}.

The second term is a "springy" repulsive term for positive \Lambda.

 

[ax3111]

okay, why do quantum fluctuations have negative pressure? What forces them to have this characteristic, and why is it different?

Okay sorry george jones, but I didn't understand any of that. My mathematics are extremely subpar to my level of understanding for the logical part of it, if that makes sense.

 

[George Jones]

okay, why do quantum fluctuations have negative pressure? What forces them to have this characteristic, and why is it different?

Here is a very rough, heuristic way to think about it.

Think of the vacuum as being a fluid, and consider a fluid element. As the universe expands, the the volume V of this fluid element expands. Event though the fluid element expands, its energy density \rho remains constant, i.e., there is "more" of the same vacuum fluid. The energy E of the fluid element is \rho V. The first law of thermodynamics then gives that

<br /> \begin{equation*}<br /> \begin{split}<br /> \Delta E &amp;= - p \Delta V \\<br /> \rho \Delta V &amp;= - p \Delta V.<br /> \end{split}<br /> \end{equation*}<br />

Consequently, p = - \rho, so, if the energy density \rho is postive, pressure p is negative.

 

[Ich]

Great explanation, george!

A little addendum to your previous post:

The weak-field limit of Einstein's equation with cosmological constant/dark energy \Lambda leads to a modified "Poisson" equation,

<br /> \nabla^2 \Phi = 4 \pi G \rho - \Lambda c^2.<br />

More generally, and with c=1, it is
<br /> \nabla^2 \Phi = 4 \pi G (\rho - 3p).<br />
And for a homogeneous source,
<br /> \vec{g} =-\frac{4}{3}\pi G (\rho - 3p) \vec{r},<br />
which is the second Friedmann equation in disguise.

 

[ax3111]

Here is a very rough, heuristic way to think about it.

Think of the vacuum as being a fluid, and consider a fluid element. As the universe expands, the the volume V of this fluid element expands. Event though the fluid element expands, its energy density \rho remains constant, i.e., there is "more" of the same vacuum fluid. The energy E of the fluid element is \rho V. The first law of thermodynamics then gives that

<br /> \begin{equation*}<br /> \begin{split}<br /> \Delta E &amp;= - p \Delta V \\<br /> \rho \Delta V &amp;= - p \Delta V.<br /> \end{split}<br /> \end{equation*}<br />

Consequently, p = - \rho, so, if the energy density \rho is postive, pressure p is negative.

So basically what you're saying is

<br /> \begin{equation*}<br /> \begin{split}<br /> \Delta E &amp;= \rho \Delta V &amp;= - p \Delta V.<br /> \end{split}<br /> \end{equation*}<br />

If I'm correct, doesn't \rho = E/v? Or is this wrong to say?

 

[George Jones]

If I'm correct, doesn't \rho = E/v? Or is this wrong to say?

Right, energy density is energy per unit volume.

 

[ax3111]

How can it be negative pressure though? That's what I don't understand.

 

[nkt]

From what i understand about DE and DM, is that it was created because the total mass didn't equate to the total energy of the universe. E=mc^2, so DE and DM was created to fill in that void.

If DE and DM existed what's to say that it actually exist in our dimensions?

According to string theory, anti-gravity (or graviton) is a (so far) fictional particle that escapes our dimension. Would this be consider as DM?