gill1109 said:
The only statistical independence required is that between the experimentally chosen measurement settings and the set of counterfactual measurement outcomes (the two pairs of outcomes of both possible measurements on both particles).
gill1109 said:
Herbert's argument (which is informal) relies on 25% and 25% and 75% being percentages of the same photon pairs. In a model which violates Bell through the detection loophole, it would be different photon pairs which are not detected with each pair of detector settings. 25% of a smaller subset of photons, 25% of another small subset of photons, 75% of yet another small subset of photons.
He is silently assuming realism by imagining the same population of photon pairs being measured in different ways.
I still don't get it... Herbert's proof doesn't even consider particles, let alone both particles or the same photon pairs.
Here is how I apply Herbert's proof to the scenario of incomplete detection, following his logic by the letter and adding my comments:
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Step One: Start by aligning both SPOT detectors. No errors are observed.
[harrylin: for example the sequences go like this:
A 10010110100111010010
B 10010110100111010010]
Step Two: Tilt the A detector till errors reach 25%. This occurs at a mutual misalignment of 30 degrees.
[harrylin: for example (a bit idealized) the sequences go like this:
A 10010100110110110110
B 10110100111010010010
This mismatch could be partly due to the detection of different photon pairs.]
Step Three: Return A detector to its original position (100% match). Now tilt the B detector in the opposite direction till errors reach 25%. This occurs at a mutual misalignment of -30 degrees.
[harrylin: for example the sequences go like this, for the same reasons:
A 10100100101011010011
B 10010101101011010101]
Step Four: Return B detector to its original position (100% match). Now tilt detector A by +30 degrees and detector B by -30 degrees so that the combined angle between them is 60 degrees.
What is now the expected mismatch between the two binary code sequences?
[..] Assuming a local reality means that, for each A photon, whatever hidden mechanism determines the output of Miss A's SPOT detector, the operation of that mechanism cannot depend on the setting of Mr B's distant detector. In other words, in a local world, any changes that occur in Miss A's coded message when she rotates her SPOT detector are caused by her actions alone.
[harrylin: apparently that includes whatever mechanism one could imagine - also non-detection of part of the photons]
And the same goes for Mr B. [..] So with this restriction in place (the assumption that reality is local), let's calculate the expected mismatch at 60 degrees.
Starting with two completely identical binary messages, if A's 30 degree turn introduces a 25% mismatch and B's 30 degree turn introduces a 25% mismatch, then the total mismatch (when both are turned) can be at most 50%. In fact the mismatch should be less than 50% because if the two errors happen to occur on the same photon, a mismatch is converted to a match.
[harrylin: and if the errors happen to occur on different photons that are compared, still sometimes a mismatch will be converted to a match. Thus now for example the sequences go like this, for the same reasons as +30 degrees and -30 degrees:
A 10101010110101010011
B 10100100101011010101]
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So far Herbert's proof, which is simply comparing binary code sequences. Nowhere is there any assumption about detection efficiency, as there is even no assumption about what happens at the detectors or about what happens at the source. The only assumptions concern independent detections and reproducibility of % of matching in sufficiently long sequences.
Where is the error?