Bogoliubov transformation / Interpretation of diagonalized Hamiltonian

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
1 reply · 2K views
Abigale
Messages
53
Reaction score
0
Hey,

I consider a diagonalized Hamiltonian:

[itex]H=\sum\limits_{k} \underbrace{ (\epsilon_{k} u_{k}^2 -\epsilon_{k} v_{k}^2 -2\Delta u_{k} v_{k} )}_{E_{k}}(d_{k \uparrow}^{\dagger}d_{k \uparrow} + d_{k \downarrow}^{\dagger}d_{k \downarrow}) +const[/itex]
with fermionic creation and annihilation operators.

From solution I know that: [itex]E_{k} =\sqrt{\Delta^2 +\epsilon_{k}^2}[/itex] but how can I get this result?





Things I even know is that: [itex]u_k^2 + v_k^2 =1[/itex] and:
[itex]\sum\limits_k <br /> <br /> \underbrace{(<br /> -2\epsilon_k u_k v_k +\Delta v_k^2 -\Delta u_k ^2<br /> )}_{\stackrel{!}{=}0}<br /> <br /> (d_{k \uparrow}^{\dagger}d_{k \downarrow}^{\dagger} + d_{k \downarrow}d_{k \uparrow})[/itex].

Thank you guys!
 
Physics news on Phys.org
Abigale said:
Things I even know is that: [itex]u_k^2 + v_k^2 =1[/itex] and:
[itex](<br /> -2\epsilon_k u_k v_k +\Delta v_k^2 -\Delta u_k ^2<br /> )=0[/itex].

This are two equations for the two unknowns u and v. Solve for them and put into the defining equation for E_k!