Bogoliubov transformation / Interpretation of diagonalized Hamiltonian

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SUMMARY

The discussion focuses on the diagonalized Hamiltonian represented by the equation H=\sum\limits_{k} (\epsilon_{k} u_{k}^2 -\epsilon_{k} v_{k}^2 -2\Delta u_{k} v_{k} )(d_{k \uparrow}^{\dagger}d_{k \uparrow} + d_{k \downarrow}^{\dagger}d_{k \downarrow}) +const. The key result derived is E_{k} =\sqrt{\Delta^2 +\epsilon_{k}^2}, which is obtained by solving the equations u_k^2 + v_k^2 =1 and -2\epsilon_k u_k v_k +\Delta v_k^2 -\Delta u_k ^2 =0 for the unknowns u and v. The discussion emphasizes the importance of these equations in deriving the energy spectrum of the system.

PREREQUISITES
  • Understanding of diagonalized Hamiltonians in quantum mechanics
  • Familiarity with fermionic creation and annihilation operators
  • Knowledge of the Bogoliubov transformation
  • Basic concepts of quantum field theory
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  • Study the derivation of the Bogoliubov transformation in detail
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Abigale
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Hey,

I consider a diagonalized Hamiltonian:

H=\sum\limits_{k} \underbrace{ (\epsilon_{k} u_{k}^2 -\epsilon_{k} v_{k}^2 -2\Delta u_{k} v_{k} )}_{E_{k}}(d_{k \uparrow}^{\dagger}d_{k \uparrow} + d_{k \downarrow}^{\dagger}d_{k \downarrow}) +const
with fermionic creation and annihilation operators.

From solution I know that: E_{k} =\sqrt{\Delta^2 +\epsilon_{k}^2} but how can I get this result?





Things I even know is that: u_k^2 + v_k^2 =1 and:
\sum\limits_k <br /> <br /> \underbrace{(<br /> -2\epsilon_k u_k v_k +\Delta v_k^2 -\Delta u_k ^2<br /> )}_{\stackrel{!}{=}0}<br /> <br /> (d_{k \uparrow}^{\dagger}d_{k \downarrow}^{\dagger} + d_{k \downarrow}d_{k \uparrow}).

Thank you guys!
 
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Abigale said:
Things I even know is that: u_k^2 + v_k^2 =1 and:
(<br /> -2\epsilon_k u_k v_k +\Delta v_k^2 -\Delta u_k ^2<br /> )=0<br />.

This are two equations for the two unknowns u and v. Solve for them and put into the defining equation for E_k!
 
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