Sho Definition and 56 Threads
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SHO with a fixed boundary
How to solve the time-independent Schodinger equation with the following potential: U(x)=x^2 for x>x0 U(x)=infinity for x<x0 ?- Dessert
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- Boundary Sho
- Replies: 1
- Forum: Advanced Physics Homework Help
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Calculating Probability of Simple Harmonic Oscillator in Phase Space
Consider a simple harmonic oscillation in 1 dimension: x(t)=Acos(wt+k). If the energy of this oscillator is btw E and E+\delta E, show that the probability the the position of the oscillator is btw x and x+dx is given by P(x)dx=\frac{1}{\pi}\frac{dx}{\sqrt{A^2-x^2}} Hint: calculate the volume...- quasar987
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- Phase Phase space Sho Space
- Replies: 0
- Forum: Advanced Physics Homework Help
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What are the energy levels and wavefunctions of a 3D SHO potential well?
We have a particle moving in a 3-D potential well V=1/2*m*(omega^2)*(r^2). we use separation of variables in cartesian coords to show that the energy levels are: E(Nx,Ny,Nz)=hbar*omega(3/2 + Nx + Ny + Nz) where Nx,Ny,Nz are integers greater than or equal to 1. Therefore we can say that...- sachi
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- 3d Potential Potential well Qm Sho
- Replies: 5
- Forum: Advanced Physics Homework Help
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.Solving [X,H] for the SHO Hamiltonian
[x, H]= ?? Given the Hamilton operator for the simple harmonic oscilator H, how do I get to [X, H]= ih(P/ m)? I put X in momentum representation, but then I can't get rid of these diff operators. mmh? thanks in advance- Ratzinger
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- Hamiltonian Sho
- Replies: 2
- Forum: Advanced Physics Homework Help
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Average potential and kinetic energy of SHO
I am using Frenches book on waves and have a question. You have a standard driven damped oscillator and I am suppose to find the average potential and kinetic energy of it. They are both similar so I will just use the potential for example. I took \frac{1}{T}\int^T_0 \frac{1}{2}KX^2 dt Where...- mewmew
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- Average Energy Kinetic Kinetic energy Potential Sho
- Replies: 1
- Forum: Advanced Physics Homework Help
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Why is the Commutator Between Ladder Operators for a SHO Not Zero?
Hi, Having trouble understanding something here, hoping someone can help...when dealing with a SHO, we can define two ladder operators a and a-dagger. The way I understand it is, applying a-dagger to an eigenstate of H (and that has, for instance, eigenvalue E) will give us a new eigenstate...- zeta101
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- Ladder operators Operators Sho
- Replies: 12
- Forum: Quantum Physics