- #1

karush

Gold Member

MHB

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$t(t-4)y'+y=0 \quad y(2)=2\quad 0<t<4$

ok my first step was isolate y'

s

$y'=-\dfrac{y}{t(t-4)}$

not sure what direction to go since we are concerned about an interval

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- MHB
- Thread starter karush
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- #1

karush

Gold Member

MHB

- 3,267

- 4

$t(t-4)y'+y=0 \quad y(2)=2\quad 0<t<4$

ok my first step was isolate y'

s

$y'=-\dfrac{y}{t(t-4)}$

not sure what direction to go since we are concerned about an interval

- #2

HOI

- 923

- 2

Well, the problem specifically says "0< t< 4" and y' does not exist at t= 0 and t= 4.

- #3

karush

Gold Member

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how does y(2)=2 fit into this

doesn't that give us specific y interval

doesn't that give us specific y interval

- #4

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You could always do "brute force" if you can't figure out a work around. Boundary conditions get rid of integration constants. Solve the differential equation. What is y(t)? What does that tell you about the solution interval(s)?how does y(2)=2 fit into this

doesn't that give us specific y interval

-Dan

- #5

HOI

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