3 dimensional vector problem .

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SUMMARY

The discussion focuses on proving the relationship cos(a) = Rz/R, where R is the resultant vector expressed as R = Rx + Ry + Rz. The solution involves recognizing that Rx, Ry, and Rz are mutually perpendicular, forming a right triangle with R as the hypotenuse. The proof can be approached using trigonometric principles or the dot product definition, which relates the angle between vectors to their components.

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  • Understanding of vector notation and components (Rx, Ry, Rz).
  • Knowledge of trigonometric functions and right triangles.
  • Familiarity with the dot product of vectors.
  • Basic principles of vector geometry.
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  • Learn about the dot product and its applications in finding angles between vectors.
  • Explore vector decomposition and its relevance in physics.
  • Review trigonometric identities and their use in vector calculations.
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Students studying physics or mathematics, particularly those focusing on vector analysis and trigonometry, as well as educators seeking to clarify concepts related to vector components and angles.

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Homework Statement


Given a vector R=Rx + Ry + Rz , prove that the cos a = Rz/R where a is the angle between vector Rz and R .


Homework Equations


I just don't know how to start .


The Attempt at a Solution

 
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Your notation isn't totally clear, but I'll assume you mean Rx, Ry and Rz to be perpendicular to each other. Then draw a triangle with sides R, Rz and Rx+Ry. Since Rz and Rx+Ry are perpendicular to each other this is a right triangle. And R is the hypotenuse. Now use trig.
 
Another way is to use the dot product, if you have had that in class. One definition of [itex]\vec{u}\cdot\vec{v}[/itex] is [itex]|\vec{u}||\vec{v}|cos(\theta)[/itex] where [itex]\theta[/itex] is the angle between [itex]\vec{u}[/itex] and [itex]\vec{v}[/itex]. Another, equivalent, definition is that the dot prouct of [itex]u_x\vec{i}+ u_y\vec{j}+ u_z\vec{k}[/itex] and [itex]v_x\vec{i}+ v_y\vec{j}+ v_z\vec{k}[/itex] is [itex]u_xv_x+ u_yv_y+ u_zv_z[/itex]. comparing those should give you then angle between [itex]R_x\vec{i}+ R_y\vec{j}+ R_z\vec{k}[/itex] and [itex]R_x\vec{i}[/itex].
 

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