5th puzzle post-the impossible sequence

[michealsmith]

o.k wats missing from the LINE UP...

9,36,225,256,400, _ ,1225,1600 .

damm, u got all the others instantly.. hope it isn't the case for this ...its a 3 step solution ...sorta ,nothing too ridiculous ,,and its slightly lateral and mensa ' ry.
goood luck
btw who ever solves it post as clearer method as possible

 

[daveb]

Well, I found a pattern, though if this is the one you’re looking for is anyone’s guess.
Take the pattern, 3, 3, 5, 4, 4, 6, 5, 5, 7,…..
Multiply it term by term with the pattern 1, 2, 3, 4, 5, 6, 7, 8
Square each one, then the pattern is
(3x1)^2 = 9
(3x2)^2 = 36
(5x3)^2 = 225
(4x4)^2 = 256
(4x5)^2 = 400
(6x6)^2 = 1296
(5x7)^2 = 1225
(5x8)^2 = 1600
So the answer is 1296

 

[michealsmith]

yep dav yep but wat r the origins of those numbers on the left ...the ones on the far left...
btw how do u make ur writting invisible i don't know how to do that

 

[davee123]

yep dav yep but wat r the origins of those numbers on the left ...the ones on the far left...
btw how do u make ur writting invisible i don't know how to do that

I'm not sure if you're looking for something else that's significant about the series 3,3,5,4,4,6,5,5,7,6,6,8,7,7,9... But essentially daveb's answer was:

F1(n) = F1(n-1)+1*(n%3)*((n-1)%3)-.5*((n-1)%3)*((n-2)%3)
F1(0) = 3

(A complicated way of getting +0, +2, -1, +0, +2, -1, +0, +2, -1, etc.)

F(n) = ((F1(n-1)+1*(n%3)*((n-1)%3)-.5*((n-1)%3)*((n-2)%3)) * (n+1))^2

As for the invisible writing, it's pretty simple-- You enter:

Now you see me

Which becomes:

Now you don't!

DaveE

 

[michealsmith]

acttually i was just going for the fact that each number represeted the amount of letters in the numbers from ...1 to 8 ...which makes it (3x6)^2 = 324