MHB 7.8.11 Find amplitude, period, PS, VS. graph 2 periods

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The discussion focuses on analyzing the function y=3cos(πx-2)+5 to determine its amplitude, period, phase shift (PS), and vertical shift (VS). The amplitude is identified as 3 and the vertical shift as 5. The period is calculated using the formula T=2π/ω, resulting in a period of 2. There is a debate regarding the phase shift, with one participant suggesting φ=2 and another indicating φ should be -2, highlighting the importance of the sign in determining the direction of the wave's shift. The conversation emphasizes the need to clarify the general form of the cosine function used in the analysis.
karush
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$\tiny{\textbf{7.8.11 Campbell HS}}$
Find (A)mplitude, (P)eriod, PS, VS. graph 2 periods
$y=3\cos(\pi x-2)+5$

by observation we have A=3 and VS=5
ok assume $\omega=\pi$
so if period is $T=\dfrac{2\pi}{\omega}$ then $T=\dfrac{2\pi}{\pi}=2$
 
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karush said:
$\tiny{\textbf{7.8.11 Campbell HS}}$
Find (A)mplitude, (P)eriod, PS, VS. graph 2 periods
$y=3\cos(\pi x-2)+5$

by observation we have A=3 and VS=5...
and $\omega=\pi$ ...
Otherwise, good!

-Dan
 
ok i think $\phi =2$ then PS is $\dfrac{\phi}{\omega}=\dfrac{2}{\pi}$

really! :unsure:
 
Okay, check with your general form of the sine wave. I use
[math]y = A ~ cos( \omega x + \phi ) + y_0[/math]

Your source might be using
[math]y = A ~ cos( \omega x - \phi ) + y_0[/math]
in which case, yes, [math]\phi = 2[/math]. In this model I'm using [math]\phi = - 2[/math]. The negative sign is important because it tells which way the wave has been shifted along the x-axis.

-Dan
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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