7.8.11 Find amplitude, period, PS, VS. graph 2 periods

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SUMMARY

The discussion focuses on finding the amplitude, period, phase shift (PS), and vertical shift (VS) of the cosine function represented by the equation $y=3\cos(\pi x-2)+5$. The amplitude (A) is determined to be 3, and the vertical shift (VS) is 5. The period (T) is calculated using the formula $T=\dfrac{2\pi}{\omega}$, resulting in a period of 2. The phase shift (PS) is derived as $\dfrac{2}{\pi}$, with a clarification on the sign of the phase shift based on the cosine function's general form.

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karush
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$\tiny{\textbf{7.8.11 Campbell HS}}$
Find (A)mplitude, (P)eriod, PS, VS. graph 2 periods
$y=3\cos(\pi x-2)+5$

by observation we have A=3 and VS=5
ok assume $\omega=\pi$
so if period is $T=\dfrac{2\pi}{\omega}$ then $T=\dfrac{2\pi}{\pi}=2$
 
Last edited:
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karush said:
$\tiny{\textbf{7.8.11 Campbell HS}}$
Find (A)mplitude, (P)eriod, PS, VS. graph 2 periods
$y=3\cos(\pi x-2)+5$

by observation we have A=3 and VS=5...
and $\omega=\pi$ ...
Otherwise, good!

-Dan
 
ok i think $\phi =2$ then PS is $\dfrac{\phi}{\omega}=\dfrac{2}{\pi}$

really! :unsure:
 
Okay, check with your general form of the sine wave. I use
[math]y = A ~ cos( \omega x + \phi ) + y_0[/math]

Your source might be using
[math]y = A ~ cos( \omega x - \phi ) + y_0[/math]
in which case, yes, [math]\phi = 2[/math]. In this model I'm using [math]\phi = - 2[/math]. The negative sign is important because it tells which way the wave has been shifted along the x-axis.

-Dan
 

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