MHB 7.8.11 Find amplitude, period, PS, VS. graph 2 periods

AI Thread Summary
The discussion focuses on analyzing the function y=3cos(πx-2)+5 to determine its amplitude, period, phase shift (PS), and vertical shift (VS). The amplitude is identified as 3 and the vertical shift as 5. The period is calculated using the formula T=2π/ω, resulting in a period of 2. There is a debate regarding the phase shift, with one participant suggesting φ=2 and another indicating φ should be -2, highlighting the importance of the sign in determining the direction of the wave's shift. The conversation emphasizes the need to clarify the general form of the cosine function used in the analysis.
karush
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$\tiny{\textbf{7.8.11 Campbell HS}}$
Find (A)mplitude, (P)eriod, PS, VS. graph 2 periods
$y=3\cos(\pi x-2)+5$

by observation we have A=3 and VS=5
ok assume $\omega=\pi$
so if period is $T=\dfrac{2\pi}{\omega}$ then $T=\dfrac{2\pi}{\pi}=2$
 
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karush said:
$\tiny{\textbf{7.8.11 Campbell HS}}$
Find (A)mplitude, (P)eriod, PS, VS. graph 2 periods
$y=3\cos(\pi x-2)+5$

by observation we have A=3 and VS=5...
and $\omega=\pi$ ...
Otherwise, good!

-Dan
 
ok i think $\phi =2$ then PS is $\dfrac{\phi}{\omega}=\dfrac{2}{\pi}$

really! :unsure:
 
Okay, check with your general form of the sine wave. I use
[math]y = A ~ cos( \omega x + \phi ) + y_0[/math]

Your source might be using
[math]y = A ~ cos( \omega x - \phi ) + y_0[/math]
in which case, yes, [math]\phi = 2[/math]. In this model I'm using [math]\phi = - 2[/math]. The negative sign is important because it tells which way the wave has been shifted along the x-axis.

-Dan
 
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