8-digit number where each digit counts occurrences of 7, 6, and 0

  • Level: High School 
  • Thread starter Thread starter harishm18
  • Start date Start date
Join the discussion
Registration is free. Start your own thread to ask a follow-up.
7 replies · 3K views
harishm18
Messages
5
Reaction score
0
main aim : You have to form a 8 digit number such that
the conditions are
the ones place stands no of 7's in the final 8 digit no that will form
the tens place stands : no of 6's in the final 8 digit no
...
...
...
then the 10^7 the place stands for no of 0's in the 8 digit no



what is the no.?
 
Mathematics news on Phys.org
Lostinthought said:
It has nly 6 digits
Count again...
:smile:
 
What about a big number-factorial_of_a_number ?
:smile: