MHB A bag contains x beads. Calculate the value of x.

  • Thread starter Thread starter Help seeker
  • Start date Start date
  • Tags Tags
    Value
Click For Summary
The problem involves calculating the total number of beads, x, in a bag containing 6 red beads and x-6 blue beads, given that the probability of drawing two beads of the same color is 9/17. The probabilities for drawing two red beads and two blue beads are calculated separately, leading to the equation 30/(x(x-1)) + ((x-6)(x-7))/(x(x-1)) = (x^2 - 13x + 72)/(x^2 - x). Setting this equal to 9/17 allows for solving for x. By cross-multiplying and simplifying, the value of x can be determined. The final solution reveals the total number of beads in the bag.
Help seeker
Messages
15
Reaction score
0
A bag contains x beads. 6 of the beads are red and the rest are blue. Ravish is going to take at random 2 beads from the bag. The probability that the 2 beads will be of the same colour is $9 /17$
Using algebra calculate the value of x. ( show sworking if possible)
 
Mathematics news on Phys.org
There are 6 red beads and x- 6 blue beads. The probability the first bead taken is red is 6/x. In that case there are 5 red beads and x- 6 blue beads left for a total of x-1 beads. The probability the second bead is also red is 5/(x- 1). The probability the two beads are both red is (6/x)(5/(x- 1))= 30/(x(x- 1)).

There are 6 red beads and x- 6 blue beads. The probability the first bead taken is blue is (x- 6)/x. In that case there are 6 red beads and x- 7 blue beads left for a total of x- 1 beads. The probability the second bead is also blue is (x- 7)/(x- 1). The probability the to beads are both blue is ((x- 6)/x)((x- 7)/(x- 1))= (x- 6)(x-7)/(x(x- 1).

The probability the two beads are the same color is 30/(x(x-1)+ ((x- 6)(x- 7)/(x(x-1))= (x^2- 13x+ 72)/(x^2- x).

Set that equal to 9/17 and solve for x.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
Replies
2
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
3
Views
3K