Solving for Minimum Duct Diameter in a Hospital Room Air Exchange System

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SUMMARY

The discussion focuses on calculating the minimum duct diameter required for a hospital room air exchange system. Given a room size of 6m x 5m x 4m, the air must be replaced every 20 minutes with a maximum air velocity of 5 m/s. Participants emphasized the importance of determining the volumetric flow rate based on the room's volume and the time constraint, leading to the application of the equation Q = A × V, where Q is the volumetric flow rate, A is the cross-sectional area, and V is the air velocity.

PREREQUISITES
  • Understanding of volumetric flow rate calculations
  • Familiarity with duct cross-sectional area formulas
  • Knowledge of air velocity and its implications in HVAC systems
  • Basic principles of fluid dynamics
NEXT STEPS
  • Calculate the volumetric flow rate for the specified room dimensions
  • Explore duct diameter calculations using the equation Q = A × V
  • Research HVAC design standards for hospital environments
  • Learn about the impact of duct design on air quality and efficiency
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Engineers, HVAC designers, and facility managers involved in the design and optimization of air exchange systems in healthcare settings.

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Q. The air in a 6m x 5m x 4m hospital room is to be completed replaced by conditioned air every 20 min. If the average air velocity in the circular air duct leading to the room is not to exceed 5 m/s, determine the minimum diameter of the duct.

We can figure out the volume of the room, knowing the dimensions then what.

time is given, what else can be done?
 
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think about volume flow rate...
 
Ok, found out volume flow rate what next
 
- You have the volume of the room that needs to be replaced every 20 minutes. That should tell you something about the volumetric flow rate needed to come out of the duct.

- If you have a flow rate, what equation also contains the duct's cross sectional area and it's velocity?

Those are two pretty big hints there.
 

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