Problem: combustion of propane, C3H8(adsbygoogle = window.adsbygoogle || []).push({});

C3H8 (g) + 5O2 (g) --- 3 CO2 (g) + 4H2O (l)

if propane reacts with oxygen as above

(a) what is the limiting reagent in a mixture containing 5.00 g of C3H8 and 10.0 g of C3H8 of O2?

(b) what mass of CO2 is formed when 1.00 g of C3H8 racts completely?

My Approach:

(a) 5.00g C3H8 x (1mol C3H8/ 44g C3H8) = .114 mol C3H8

10.0g O2 x (1mol C3H8/ 32g O2) = .313 mol O2

C3H8 is limiting

(b) 1.00g C3H8 x (1 mol C3H8/ 44g C3H8) x (3mol CO2/ 1mol C3H8) x (44g CO2/ 1 mol CO2) =3.00g CO2

I'm kinda doubting my answer on the limiting reagent part...can someone explain it to me if im wrong?

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: A limiting Reagent Problem: Check My work!

**Physics Forums | Science Articles, Homework Help, Discussion**