- #1

cheechnchong

- 132

- 1

C3H8 (g) + 5O2 (g) --- 3 CO2 (g) + 4H2O (l)

if propane reacts with oxygen as above

(a) what is the limiting reagent in a mixture containing 5.00 g of C3H8 and 10.0 g of C3H8 of O2?

(b) what mass of CO2 is formed when 1.00 g of C3H8 racts completely?

My Approach:

(a) 5.00g C3H8 x (1mol C3H8/ 44g C3H8) = .114 mol C3H8

10.0g O2 x (1mol C3H8/ 32g O2) = .313 mol O2

**C3H8 is limiting**

(b) 1.00g C3H8 x (1 mol C3H8/ 44g C3H8) x (3mol CO2/ 1mol C3H8) x (44g CO2/ 1 mol CO2) =

**3.00g CO2**

I'm kinda doubting my answer on the limiting reagent part...can someone explain it to me if I am wrong?