sickenz said:
If time passes so much slower near the speed of light... What would happen if someone on Earth made a 10 minute phone call to someone traveling at the speed of light? In this case, the 10 minutes would be relative to a watch from the person on Earth and a watch from the person moving near light speed. So time in this case is not a perception by either person in the given scenario, it is defined by a static object that can only perceive time in one way and only one way.
I'm sure this has quite a simple answer; I am new to understanding GR and quantum theories. Since this is a question I came up with myself, I'm hoping a solid answer will help define my sense of logic, propelling me further into such an interesting field of study.
Also, I apologize in advance if this topic is misplaced or if similar questions have been recently answered.
Thank you!
First off, as phyzguy pointed out, you can't travel at the speed of light so let's assume the traveler is going at 96% of the speed of light. I like that number because it allows us to get an exact solution instead of one with a lot of digits past the decimal.
Secondly, you didn't specify which direction the traveler was moving with respect to the person on Earth but you did stipulate that the phone call will take ten minutes for both the Earth person and for the traveler as defined by their own watches.
Thirdly, this problem has nothing to do with Time Dilation or with frames of reference and it is not even a problem that requires Special Relativity to solve, although we can use SR to help us solve it. Instead, it is a problem having to do with Relativistic Doppler and at 96%c the Doppler factor is exactly 7 or its reciprocal.
Now let's see how we can set up a scenario to accomplish what you want. Let's suppose the traveler is far away from Earth and traveling almost directly towards Earth. He's going to fly right past Earth during the phone call and then be traveling away from Earth.
While the traveler is approaching Earth at 96%c, the Relativistic Doppler shift is 7. That means that when he gets the phone call from Earth, he will hear the voice of the Earth person sped up 7 times faster than normal and taking 1/7 of the length of time. Clearly, if he was really far away, the ten minute call would only last for less than a minute and a half.
But let's suppose that he has already passed Earth when the phone call is made. Now he will hear the Earth person speaking very slowly, 1/7th of normal and the phone call will take 70 minutes to happen according to his watch.
So, in order to get this phone call to last ten minutes according to the traveler, we just have to solve a mathematical problem. Let t1 be the time according to the traveler's watch prior to him passing Earth and t2 be his time after passing Earth. We want t1+t2 to be equal to 10. But we also need for t1*7 + t2/7 to equal 10.
t1+t2=10
t1*7 + t2/7 = 10
t1*49 + t2 = 70
t2 = 10 - t1
t1*49 - t1 + 10 = 70
t1*48 = 70 -10 = 60
t1 = 60/48 = 1.25
t2 = 10 - 1.25 = 8.75
So we just make sure that the traveler spends 1.25 minutes receiving the first part of the phone call at 7 times normal which means that the Earth guy will be talking for 8.75 minutes and then just when the traveler passes Earth, he spends 8.75 minutes talking to the Earth guy who will hear it come in at 1/7 of normal speed.
So they both get to talk for 8.75 minutes and they listen for 1.25 minutes for a total time of ten minutes according to both of their watches.
That was fun although I'm sure it isn't what you expected. Nevertheless, this is the sort of thing that happens when a scenario is ill-defined.