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## Main Question or Discussion Point

Given

[x,p] = i * h-bar,

prove that

<p|X|p'> = [i * h-bar / (p' - p)] * δ(p - p').

I don't understand why commutator matters with this proof?

[x,p] = i * h-bar,

prove that

<p|X|p'> = [i * h-bar / (p' - p)] * δ(p - p').

I don't understand why commutator matters with this proof?