A question on alternating current

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SUMMARY

The discussion centers on calculating the root-mean-square (RMS) voltage across a 1500W device with a peak current of 5.4A. The user correctly applies the formula for peak current, deriving an RMS current of 3.82A. Subsequently, they use the relationship between power, RMS current, and RMS voltage to find the RMS voltage, concluding it to be 392.84V. The method employed is confirmed as accurate, despite the user's initial uncertainty regarding its simplicity.

PREREQUISITES
  • Understanding of alternating current (AC) concepts
  • Familiarity with root-mean-square (RMS) calculations
  • Knowledge of electrical power formulas (P = IV)
  • Basic algebra skills for manipulating equations
NEXT STEPS
  • Study the derivation of RMS values in AC circuits
  • Learn about the relationship between peak and RMS values in AC systems
  • Explore advanced AC circuit analysis techniques
  • Investigate power factor and its impact on AC power calculations
USEFUL FOR

Electrical engineering students, educators teaching AC circuit theory, and professionals working with alternating current systems will benefit from this discussion.

Kudo Shinichi
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Homework Statement


The peak value of an alternating current in a 1500W device is 5.4A. What is the rms voltage (root-mean-square voltage)across it?

The Attempt at a Solution


Peak current=sqrt(2)*Irms
5.4A=sqrt(2)*Irms
Irms=3.82A
Irms=P/Vrms
3.82=1500/Vrms
Vrms=392.84V

I am not sure whether this is the correct way to do the question or not, because it seems to simple...Any comment/help would be great. Thank you very much.
 
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This is, in fact, the correct way to do it, easy though it may seem.
 
jdougherty said:
This is, in fact, the correct way to do it, easy though it may seem.

thank you very much^^
 

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