A set A of n elements has n(n-1)/2 subsets of 2 elements

AI Thread Summary
A finite set A with n elements has n(n-1)/2 subsets of two elements, which can be proven using mathematical induction. The base case for n=2 confirms there is 1 subset of two elements. Assuming the hypothesis holds for n=k, the goal is to demonstrate it for n=k+1. By adding a new element to the set, k new subsets can be formed that include this new element, leading to the conclusion that the formula holds for n=k+1. This approach effectively shows that the number of subsets increases as expected, validating the original statement.
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I would very much like some help to the following problem.

Homework Statement



Using mathematical induction, prove that a finite set A of n elements has n(n-1)/2 subsets of two elements.

The Attempt at a Solution



* Base step n=2: 2(2-1)/2= 1 subset of two elements.
* Inductive step: assuming the statement holds for n=k, that is a set A of k elements has k(k-1)/2 (hypothesis)
We want to show that it also holds for n=k+1, that is a set A of k+1 has (k+1)(k+1-1)/2 elements.
How can we infer from the hypothesis ? I have no idea ...

I have an engineering background so be as descriptive as you can.
Thank you in advance.
 
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dpesios said:
* Base step n=2: 2(2-1)/2= 1 subset of two elements.
* Inductive step: assuming the statement holds for n=k, that is a set A of k elements has k(k-1)/2 (hypothesis)
We want to show that it also holds for n=k+1, that is a set A of k+1 has (k+1)(k+1-1)/2 elements.
A set A of k elements has k(k-1)/2 subsets of two elements, as you said.
Suppose you add a new element to set A. How many new subsets can be created where one of the elements of these subsets is the new element?
 
if we add an element to the set which previously had k elements (that is now has k+1 elements) the new subsets that include the new element will be :

(k+1)k/2 - k(k-1)/2 = k

So, how can we argue that this will solve the problem ?
 
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