A set A of n elements has n(n-1)/2 subsets of 2 elements

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SUMMARY

A finite set A of n elements has exactly n(n-1)/2 subsets of two elements, as proven through mathematical induction. The base case for n=2 confirms that there is 1 subset, while the inductive step shows that if the hypothesis holds for n=k, it also holds for n=k+1. By adding a new element to the set, k new subsets can be formed, reinforcing the validity of the hypothesis. This structured approach effectively demonstrates the relationship between the number of elements and the subsets of two elements.

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dpesios
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I would very much like some help to the following problem.

Homework Statement



Using mathematical induction, prove that a finite set A of n elements has n(n-1)/2 subsets of two elements.

The Attempt at a Solution



* Base step n=2: 2(2-1)/2= 1 subset of two elements.
* Inductive step: assuming the statement holds for n=k, that is a set A of k elements has k(k-1)/2 (hypothesis)
We want to show that it also holds for n=k+1, that is a set A of k+1 has (k+1)(k+1-1)/2 elements.
How can we infer from the hypothesis ? I have no idea ...

I have an engineering background so be as descriptive as you can.
Thank you in advance.
 
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dpesios said:
* Base step n=2: 2(2-1)/2= 1 subset of two elements.
* Inductive step: assuming the statement holds for n=k, that is a set A of k elements has k(k-1)/2 (hypothesis)
We want to show that it also holds for n=k+1, that is a set A of k+1 has (k+1)(k+1-1)/2 elements.
A set A of k elements has k(k-1)/2 subsets of two elements, as you said.
Suppose you add a new element to set A. How many new subsets can be created where one of the elements of these subsets is the new element?
 
if we add an element to the set which previously had k elements (that is now has k+1 elements) the new subsets that include the new element will be :

(k+1)k/2 - k(k-1)/2 = k

So, how can we argue that this will solve the problem ?
 

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