A Single Turn, Square Loop (torque)

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DeltaIceman
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Homework Statement


A 0.790 m length of wire is formed into a single-turn, square loop in which there is a current of 12.4 A. The loop is placed in a magnetic field of 0.146 T, as shown in the figure below.

http://img294.imageshack.us/img294/5043/cutj2167.gif

Homework Equations



Net torque = NIABsin(theta)


The Attempt at a Solution


Okay so looking at the problem. I see that a wire the length of .790 is bent to for a single-turn square. So I take my length and divide it by 2. Which should be the length of each side of the square now.
Now the area of a square is A = l*w or one of your sides squared. So that would give me an A of .156 m^2.

Now as for N should it not just be 1. Since its a single turn square.

B = .146
I = 12.4
Also since I am looking for the maximum torque it should be a sin(90) correct?

Well anyway when I use this formula I'm not getting the correct answer. So if someone could steer me in the right direction that would be great :).
 
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DeltaIceman said:

Homework Statement


A 0.790 m length of wire is formed into a single-turn, square loop in which there is a current of 12.4 A.

The Attempt at a Solution


I see that a wire the length of .790 is bent to for a single-turn square. So I take my length and divide it by 2. Which should be the length of each side of the square now.

How many sides does a square have?

ehild
 
A square has 4 sides. But since its a single loop square doesn't it only have 2 sides?
 
I mean not that the square in general has 2 sides. I know that's not possible. But I thought that when it said a single turn it meant that the length .709 was the first 2 sides of the square... |_ <- like that if it makes sense. And I just divided the length by 2 to get the length of one side. Anyway that's what I think of when it says single turn.
 
Well, it might have been better to say "single loop" in the problem. You need the area of the loop to get the torque. A single turn "L" shape has no area. ehild