1. The problem statement, all variables and given/known data A stubborn, 100.0kg mule sits down and refuses to move. To drag the mule to the barn, the exasperated farmer ties a rope around the mule and pulls with his maximum force of 826.0N. The coefficients of friction between the mule and the ground are s=0.800 and k=0.220. What is the net force on the mule? 3. The attempt at a solution ok, so the original question was 144kg mule, but i changed the numbers around to make the force greater than static friction. 100x 9.8 x 0.8 =784N since the applied force is greater than static force, we know that mule is moving. BUT, the net force is not 826 - 784 right because we need to use kinetic friction. so 100 x 9.8 x 0.22 =215N. so net force is 826 - 215 =611N BUT if the question what is the net force when the mule just started to move, will it be 826 - 784 = 42N? but that's such a big difference of net force.. Can someone check both of my calculations and reasoning?