Calculating Final Speed in Elastic Collision: Uranium Atom and Hydrogen Molecule

Click For Summary
In an elastic collision between a uranium atom traveling at 4 m/s and a stationary hydrogen molecule, the final speed of the hydrogen molecule is approximately 8 * 10^4 m/s. The discussion emphasizes the importance of using conservation laws and relevant equations for elastic collisions. It highlights the need to consider the relative masses of the particles involved in the calculation. The attempt to solve the problem involved misconceptions about momentum and direction post-collision. Understanding these principles is crucial for accurately determining the final speeds in such collisions.
weizhi li
Messages
1
Reaction score
0

Homework Statement


a uranium atom traveling at speed 4 *
cramster-equation-20095141845396337792353984075008046.gif
m/s collides elastically with astationary hydrogen molcule. head on. what is the approximate finalspeed of the hydrogen molecule?

Homework Equations


The answer is about 8*10^4 m/s

But, i tried many times and failed.

The Attempt at a Solution


MY thought is that the speed of uranium atom after collision should be the same but in different direction, which means the momentum of hydrogen after collision is 2*p1(p1 is uranium momentum before collision). and use this to calculate the speed by plugging into the formula k = p^2 / 2m
 
Physics news on Phys.org
The problem is an exercise in elastic collision. Your relevant equations should include formulas that pertain to elastic collisions. In particular, the conservation laws that are applicable. You also need to look up the relative masses of the particles in question.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 13 ·
Replies
13
Views
1K
Replies
20
Views
2K
  • · Replies 16 ·
Replies
16
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 15 ·
Replies
15
Views
4K
Replies
10
Views
3K
  • · Replies 15 ·
Replies
15
Views
3K
  • · Replies 22 ·
Replies
22
Views
4K
Replies
3
Views
994