Absolute Value Equations: Solving |2x-8| + |12-3x| = 0

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SUMMARY

The equation |2x-8| + |12-3x| = 0 can be solved by recognizing that both absolute values must equal zero for the equation to hold true. This leads to the conditions 2x - 8 = 0 and 12 - 3x = 0, which simplifies to x = 4. The solution is confirmed as x = 4, as both expressions equal zero at this point. The discussion highlights the importance of setting each absolute value expression to zero when the overall equation equals zero.

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  • Basic algebraic manipulation skills
  • Knowledge of solving linear equations
  • Familiarity with the properties of equality
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  • Learn techniques for solving absolute value inequalities
  • Explore graphing absolute value equations for visual understanding
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Nelo
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Homework Statement



|2x-8| + |12 - 3x | = 0



Homework Equations



what do i do when it = 0

The Attempt at a Solution



I tried solving it like all the others, but i know there is a unique thing to do when it = 0, i jus don't know what.

So , here's what i did.

2|x-4| + -3|x-4| = 0
-|x-4| = 0

x > 4

(-)x-4 = 0
-x = 4
x = -4

x < 4

(-)-x+4 = 0
x+4 = 0
x = - 4.

The answer is 4, I just probably set the normal one up wrong, what am i doing wrong?
 
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Nelo said:

Homework Statement



|2x-8| + |12 - 3x | = 0



Homework Equations



what do i do when it = 0

The Attempt at a Solution



I tried solving it like all the others, but i know there is a unique thing to do when it = 0, i jus don't know what.

So , here's what i did.

2|x-4| + -3|x-4| = 0
-|x-4| = 0

x > 4

(-)x-4 = 0
-x = 4
x = -4

x < 4

(-)-x+4 = 0
x+4 = 0
x = - 4.

The answer is 4, I just probably set the normal one up wrong, what am i doing wrong?

|12 - 3x | = |3x - 12| = 3|x - 4|
 

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