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Absolutely central elastic collision (or translate lying)

  • #1

Homework Statement


2 balls, their size is the same but mass is different, they are going towards a collision. I do not know what is the word for it in english but its like this m1= 1,2m2. Speed of the balls are v1=12m/s and v2= 15m/s.Calculate the speed of each ball after absolutely central elastic collision.

Homework Equations


p=mv
p=p,

The Attempt at a Solution


I could not even think of a solution since I missed out some classes.
 

Answers and Replies

  • #2
Doc Al
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What's conserved in an elastic collision?
 
  • #3
BvU
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I don't see the connection between the relevant equations and the attempt at solution ?
 
  • #4
What's conserved in an elastic collision?
I don't see the connection between the relevant equations and the attempt at solution ?
yes all i can write is p1= 1,2m2 x 12 = 14,4m2 but i cant get past this part, the p= p, is just a reminder for me. And i think that its kinetic energy thats being conserved.
 
  • #5
Doc Al
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the p= p, is just a reminder for me.
It should remind you that momentum is conserved.

And i think that its kinetic energy thats being conserved.
Right.

So combine those two conservation laws.
 
  • #6
Its going to be hard since english is not my born language. so i couldnt figure it out so i looked on the internet and this is what i got K = 1/2m(p/m)2= p2/2m
 
  • #7
Doc Al
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Its going to be hard since english is not my born language. so i couldnt figure it out so i looked on the internet and this is what i got K = 1/2m(p/m)2= p2/2m
That's just expressing the kinetic energy in terms of momentum instead of velocity. That won't help you.

You need to write equations for:
  • conservation of energy
  • conservation of momentum
I assume you have a textbook. I suspect it gives examples of this sort of collision.
 
  • #8
As I said before I missed out on some classes, they were doing the similar but easier tasks and I did not ask for their notes so that is my fault. Conservation of momentum is m1xdv1=-m2xdv2 as it says. And Energy i dont know that, or maybe its because of the differences in language.
 
  • #9
Doc Al
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Conservation of momentum is m1xdv1=-m2xdv2 as it says.
There are four velocities involved: The initial and final velocities of each object.

And Energy i dont know that, or maybe its because of the differences in language.
I don't think language has much to do with it. :smile:

Again, check your textbook.

And read this: Wiki: Elastic Collisions in one dimension
 
  • #10
There are four velocities involved: The initial and final velocities of each object.
so you mean i should do it like this ?
e963c8486037693393e095efaa207565.png
or this
0500891e166dc265e76febfa8a06a8bf.png
? And about that energy, i could not find anything but Ek= Ek'. There is also this ∑p = constant but i doubt it, also Ek= mv2/2 but also i doubt that. Only equation that i think would be right is the first one. :/. I have something to add
m1v1 + m2v2 =[m1+m2]v3 mayb e this
 
Last edited:
  • #11
Doc Al
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Both conservation equations are given in that Wiki link. They even solve them for you!
 
  • #12
Both conservation equations are given in that Wiki link. They even solve them for you!
so basically
d764d6a70dd21fb0a5a801f5b0e6e10a.png
this is the momentum equation as it says and this
7901fde5f0d74ca583013c3f86135133.png
is energy equation.
and i get
ab6645eaf09c6da1ba47b0f662615140.png

e0fa187fc3065bad45710620be5f7687.png
by combining them ?
 
  • #13
Doc Al
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That's correct. (But you'd better understand how to solve those equations.)
 
  • #14
You want me to put numbers in those equations or understand how i got the combinations, i have a hard time understanding what comes next.
 
  • #15
haruspex
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You want me to put numbers in those equations or understand how i got the combinations, i have a hard time understanding what comes next.
Yes, just plug the numbers in.
By the way, the correct translation is probably "head-on elastic collision", i.e. the mass centres, direction of relative motion and point of impact are all in a straight line.
 

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