Acceleration at incline with friction

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The discussion revolves around calculating the acceleration of a 250 kg block on five different inclined planes with varying angles and coefficients of friction. The inclines are categorized by angles of 22 degrees and 10 degrees, with respective friction coefficients ranging from 0.1 to 0.5. Initial calculations for acceleration yielded incorrect rankings, prompting a reevaluation of the calculations, particularly for incline B. The correct ranking of accelerations needs to account for both the angle of incline and the frictional forces involved. Accurate calculations are essential for determining the correct order of acceleration from smallest to largest.
SilentBlade91
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Homework Statement



A block of mass 250 kg is placed at rest onto 5 different inclines. The angle of incline A is
22o,
B is at 22o,
C is at 22o,
D is at 10o, and
E is at 10o.
The inclines are made of different materials, and have coefficients of friction
mkA = 0.3,
mkB = 0.4,
mkC = 0.5,
mkD = 0.2, and
mkE = 0.1.
For each incline, the static friction is only marginally higher than the kinetic friction.
Rank the magnitude of the acceleration of the block on each incline, from smallest to largest. For ties, list answers alphabetically.


Homework Equations



F=ma
Frictional force equation

The Attempt at a Solution



I tried and got these values: A: .945224m/s^2
B: .036584m/s^2
C: -.872056m/s^2
D: -.228472m/s^2
and E: .73664m/s^2

so I tried C,D,B,E,A but it was wrong :-(
 
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Try B again, it doesn't look like you've calculated it correctly.
 
Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

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