Accuracy of HIV test - probability

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DannyCov
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Hi everone,

Really stuck on this one, if anyone has any suggestions I would be more than greatful!

Problem:
A HIV test detects at 90% accuracy
It falsly detects people as positive without HIV at 2%
and it is estimated that 50% of the tested patients have HIV

I need to work out the probability that a person does not have HIV and the test is negative?

... but first I am still confused to how to separate all the conditions, my teacher suggested using contingency tables but the ones I draw up don't make sense to me

Can anyone help?
 
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You know Bayes theorum?

anyhow,
probability that person is HIV negative=1/2
probability of false positive=0.02
therefore (1-.02)=probability of accurate result
product of .5(.98) is what I think you want.
 
Ah great thanks that's the way I approached it. The next thing they ask is very vague...
they ask the probability a woman has hiv if the result is positive?
No where else in the question do they say women are any more likely than men so I assume the answer to be another condional probability
P(woman,tumor, PositiveTest)= 0.5 * 0.5 * 90

is this reasonable?
 
hmmm, that is vague. I would simply exclude the sex reference and suggest 0.9
as there is no refernce to any notion that false positives are more likely in women than men, so i would interpret the question as a person...